Determine the points of intersection of the function
With the X
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Determine the points of intersection of the function
With the X
To solve this problem, we'll determine where the graph of the function intersects the x-axis by following these steps:
Now, let's apply these steps:
Step 1: Set the equation to zero: .
Step 2: Solve for .
Step 3: The solutions represent points on the x-axis where the function intersects.
Thus, the points of intersection are and .
Therefore, the solution to the problem is .
The following function has been graphed below:
\( f(x)=-x^2+5x+6 \)
Calculate points A and B.
X-intercepts are where the graph crosses the x-axis. Since the x-axis is the line y = 0, any point on it must have a y-coordinate of 0!
For y-intercepts, you set x = 0 and solve for y. For x-intercepts, you set y = 0 and solve for x. They're opposite processes!
You'd need to factor the quadratic first, then set each factor equal to zero. Factored form like makes finding x-intercepts much easier!
No! A quadratic function can have at most 2 x-intercepts, exactly 1, or none at all. This one has exactly 2 since both factors give different x-values.
We want to find where the graph crosses the x-axis, which means where y = 0. Setting the function equal to zero gives us those special x-values!
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