Find the intersection of the function
With the X
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Find the intersection of the function
With the X
To find the intersection of the function with the x-axis, we set since intersections on the x-axis have a -coordinate of zero.
Therefore, our equation becomes:
.
To solve this equation, take the square root of both sides:
.
Next, solve for by subtracting from both sides:
.
Thus, the intersection point of the function with the x-axis is .
After checking the provided answer choices, the correct choice is:
Therefore, the solution to the problem is .
Find the intersection of the function
\( y=(x-2)^2 \)
With the X
X-intercepts are points where the graph crosses the x-axis. At these points, the y-coordinate is always zero. So setting y = 0 helps you find exactly where this happens!
That's completely normal! Negative x-values just mean the intercept is to the left of the origin. The point is still a valid x-intercept.
This parabola is in perfect square form , which means it just touches the x-axis at one point. It's like the tip of a U-shape sitting on the x-axis.
You can write as or 1.25. Use whichever form feels more comfortable for your calculations!
When finding x-intercepts, you need the complete coordinate pair. You solve for the x-value, but the final answer is because y is always 0 at x-intercepts.
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