Find Y-Intercept of y=(x-5)²: Quadratic Function Analysis

Question

Find the intersection of the function

$y=(x-5)^2$

With the Y

00:00 Find the intersection point of the function with the Y-axis

00:03 At the intersection point with the Y-axis X =0

00:08 Therefore substitute X =0 and solve to find the intersection point with the Y-axis

00:23 This is the Y value at the intersection point, substitute X=0 as we did at the point

00:28 And this is the solution to the question

To find the intersection of the function $y = (x-5)^2$ with the y-axis, we follow these steps:

Let's calculate:
- Substitute $x = 0$ into the function: $y = (0-5)^2$ .
- Simplifying further, $y = (-5)^2 = 25$ .

Thus, the intersection of the function $y = (x-5)^2$ with the y-axis occurs at the point $(0, 25)$ .

Therefore, the correct answer is $(0, 25)$ .

$(0,25)$