Find X-Axis Intersections of y=(x+3)² : Quadratic Function Analysis

X-Axis Intersections with Perfect Square Quadratics

Find the intersection of the function

y=(x+3)2 y=(x+3)^2

With the X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the intersection point of the function with the X-axis
00:03 At the intersection point with the X-axis Y =0
00:07 Therefore, we substitute Y =0 and solve to find the intersection point with the X-axis
00:11 Extract the root to eliminate the power
00:24 Isolate X
00:31 This is the X value at the intersection point, we substitute Y=0 as we stated at the point
00:36 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the intersection of the function

y=(x+3)2 y=(x+3)^2

With the X

2

Step-by-step solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the function as y=(x+3)2 y = (x+3)^2 .
  • Step 2: Set y=0 y = 0 to find the intersection with the x-axis.
  • Step 3: Solve (x+3)2=0 (x+3)^2 = 0 to find the x-coordinate.

Let's proceed through each step:
Step 1: We are given the function y=(x+3)2 y = (x+3)^2 .
Step 2: To find where this function intersects the x-axis, set y=0 y = 0 :

(x+3)2=0 (x+3)^2 = 0

Step 3: Solve the equation:
The equation (x+3)2=0 (x+3)^2 = 0 suggests that x+3=0 x+3 = 0 ,
which simplifies to x=3 x = -3 .

Therefore, the intersection point is where x=3 x = -3 and y=0 y = 0 , giving us the intersection at (3,0) (-3, 0) .

Thus, the solution to the problem is (3,0)(-3, 0), corresponding to choice given as (3,0)(-3, 0).

3

Final Answer

(3,0) (-3,0)

Key Points to Remember

Essential concepts to master this topic
  • X-Intercepts: Set y = 0 to find where function crosses x-axis
  • Perfect Square: (x+3)2=0 (x+3)^2 = 0 means x + 3 = 0, so x = -3
  • Verify: Substitute x = -3: y=(3+3)2=02=0 y = (-3+3)^2 = 0^2 = 0

Common Mistakes

Avoid these frequent errors
  • Expanding the perfect square unnecessarily
    Don't expand (x+3)2 (x+3)^2 to x2+6x+9=0 x^2 + 6x + 9 = 0 then use quadratic formula = harder work for same answer! Perfect squares already show the solution directly. Always recognize (x+a)2=0 (x+a)^2 = 0 means x = -a immediately.

Practice Quiz

Test your knowledge with interactive questions

Find the intersection of the function

\( y=(x+4)^2 \)

With the Y

FAQ

Everything you need to know about this question

Why is there only one x-intercept instead of two?

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Great observation! Most quadratics have two x-intercepts, but y=(x+3)2 y = (x+3)^2 is special. It touches the x-axis at exactly one point: (3,0) (-3, 0) . This is called a double root because the parabola just touches the axis without crossing it.

How do I know when to set y = 0?

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Always set y = 0 when finding x-intercepts! The x-axis is where y-coordinates equal zero. Think of it this way: "Where does my graph touch the ground (y = 0)?"

What if I get confused about the sign?

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Remember: (x+3)2=0 (x+3)^2 = 0 means x + 3 = 0, so x = -3. The intercept is at (3,0) (-3, 0) , not (3,0) (3, 0) ! Always solve the equation inside the parentheses.

Can I check my answer another way?

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Yes! Graph the function or use a table of values. You'll see that when x = -3, y = 0, confirming your intercept. You can also substitute: y=(3+3)2=02=0 y = (-3+3)^2 = 0^2 = 0

Why are the other answer choices wrong?

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(3,0) (3, 0) comes from the wrong sign. (0,3) (0, 3) and (0,3) (0, -3) are y-intercepts (where x = 0), not x-intercepts. Always check which axis you're finding intersections with!

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