Finding the Translated Parabola: y=x² with Root at x=4

Question

Which parabola is the translation of the graph of the function y=x2 y=x^2

and is positive in all areas except x=4 x=4 ?

Video Solution

Solution Steps

00:00 Find the correct function according to the data
00:03 We'll use the positive domain, from this we understand that the parabola smiles:
00:07 Meaning a positive coefficient for X squared
00:12 We'll draw the function according to the intersection points and type of parabola
00:16 Shift on X-axis depends on term P
00:25 We'll substitute in the parabola formula and solve to find the function
00:29 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the desired vertex of the parabola.
  • Step 2: Use the vertex form of the parabola, y=(xh)2+k y = (x - h)^2 + k .
  • Step 3: Verify the solution with problem constraints.

Now, let's work through each step:
Step 1: We need the parabola to have a vertex such that it equals zero at x=4 x = 4 . Thus, the vertex is (4,0) (4, 0) .
Step 2: Using the vertex form, substitute h=4 h = 4 and k=0 k = 0 into y=(xh)2+k y = (x - h)^2 + k , resulting in y=(x4)2 y = (x - 4)^2 . This equation ensures that y=0 y = 0 only when x=4 x = 4 .
Step 3: This parabola is positive for values of x x other than 4, as the square of any nonzero number is positive. Thus, it meets the specified condition of being positive except at x=4 x = 4 .

Therefore, the solution to the problem is y=(x4)2 y = (x - 4)^2 .

Answer

y=(x4)2 y=(x-4)^2