Parabola Translation: Finding y=x² Shift with Exception at x=-3

Question

Which parabola is the translation of the graph of the function y=x2 y=x^2

and is positive in all areas exceptx=3 x=-3 ?

Video Solution

Solution Steps

00:00 Find the correct function according to the data
00:03 We'll use the positive domain, understanding from this that the parabola smiles
00:08 Meaning a positive coefficient for X squared
00:12 We'll draw the function according to the intersection points and type of parabola
00:16 Left shift depends on the P term
00:27 We'll substitute in the parabola formula and solve to find the function
00:35 Negative times negative always equals positive
00:41 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the necessary translation of the parabola.
  • Step 2: Apply the translation to the equation of the parabola.

Now, let's work through each step:

Step 1: We are given the function y=x2 y = x^2 . The new parabola must be zero at x=3 x = -3 and positive everywhere else. This means the vertex of the parabola is at (3,0) (-3, 0) .

Step 2: To move the vertex of y=x2 y = x^2 from (0,0) (0, 0) to (3,0) (-3, 0) , we need a horizontal shift to the left by 3 units. The translation is represented by replacing x x with x+3 x + 3 in the function:

y=(x+3)2 y = (x + 3)^2

This new equation reflects a parabola that opens upwards and has its vertex at (3,0)(-3, 0), which means it is zero only at x=3 x = -3 and positive everywhere else.

Therefore, the solution to the problem is y=(x+3)2 y = (x + 3)^2 .

Answer

y=(x+3)2 y=(x+3)^2