Parabola Translation: Finding y=x² Shift with Exception at x=-3

Parabola Translation with Vertex Shifts

Which parabola is the translation of the graph of the function y=x2 y=x^2

and is positive in all areas exceptx=3 x=-3 ?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's find the correct function based on the data we have.
00:12 We'll use the positive side and see that the parabola smiles.
00:16 This means the coefficient for X squared is positive.
00:21 We'll sketch the function using intersection points and the parabola type.
00:26 The shift to the left depends on the value of the P term.
00:35 Let's substitute into the parabola formula and solve for the function.
00:43 Remember, negative times negative equals positive.
00:49 And that's how we find the solution to our problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Which parabola is the translation of the graph of the function y=x2 y=x^2

and is positive in all areas exceptx=3 x=-3 ?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the necessary translation of the parabola.
  • Step 2: Apply the translation to the equation of the parabola.

Now, let's work through each step:

Step 1: We are given the function y=x2 y = x^2 . The new parabola must be zero at x=3 x = -3 and positive everywhere else. This means the vertex of the parabola is at (3,0) (-3, 0) .

Step 2: To move the vertex of y=x2 y = x^2 from (0,0) (0, 0) to (3,0) (-3, 0) , we need a horizontal shift to the left by 3 units. The translation is represented by replacing x x with x+3 x + 3 in the function:

y=(x+3)2 y = (x + 3)^2

This new equation reflects a parabola that opens upwards and has its vertex at (3,0)(-3, 0), which means it is zero only at x=3 x = -3 and positive everywhere else.

Therefore, the solution to the problem is y=(x+3)2 y = (x + 3)^2 .

3

Final Answer

y=(x+3)2 y=(x+3)^2

Key Points to Remember

Essential concepts to master this topic
  • Translation Rule: Replace x with (x + h) to shift left h units
  • Technique: To shift from (0,0) to (-3,0), use y = (x + 3)²
  • Check: At x = -3: y = (-3 + 3)² = 0, elsewhere y > 0 ✓

Common Mistakes

Avoid these frequent errors
  • Confusing horizontal shift direction with sign
    Don't think y = (x - 3)² shifts left to x = -3! This actually shifts right to x = 3, making the vertex at (3,0) instead. Always remember: (x + h) shifts LEFT h units, (x - h) shifts RIGHT h units.

Practice Quiz

Test your knowledge with interactive questions

Find the intersection of the function

\( y=(x+4)^2 \)

With the Y

FAQ

Everything you need to know about this question

Why does (x + 3)² shift the parabola to the LEFT when it has a plus sign?

+

This confuses many students! Think of it this way: (x + 3)² = 0 when x = -3. The parabola reaches its minimum (vertex) where the expression inside equals zero. So x + 3 = 0 means x = -3, placing the vertex at x = -3.

How do I remember which direction horizontal shifts go?

+

Use the "opposite rule": The sign inside the parentheses is opposite to the shift direction. (x + 3) shifts LEFT 3 units, (x - 3) shifts RIGHT 3 units. Always solve for when the expression equals zero!

What does 'positive in all areas except x = -3' really mean?

+

This means the parabola touches the x-axis at exactly one point: x = -3. Everywhere else, the y-values are above the x-axis (positive). The vertex must be at (-3, 0) with the parabola opening upward.

Could the answer be y = -(x + 3)² since it's also zero at x = -3?

+

No! While y = -(x + 3)² is zero at x = -3, it's negative everywhere else (opens downward). We need the parabola to be positive except at x = -3, so it must open upward.

How can I quickly check my answer?

+

Test three points: x = -3 (should give y = 0), x = -2 (should be positive), and x = -4 (should be positive). For y = (x + 3)²: at x = -2, y = 1 ✓; at x = -4, y = 1 ✓

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