Finding X-Axis Intersections: Zero Substitution Method

To work out the points of intersection with the X axis, you must substitute x=0 x=0 .

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 To find the intersection point with the X-axis, we substitute X = 0?
00:03 Let's draw a parabola that has intersection points with the X-axis
00:12 This is the line where X = 0 (Y-axis)
00:16 At the intersection points with the X-axis on the graph, we can see they are not 0
00:22 At the intersection points with the X-axis - Y = 0
00:26 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

To work out the points of intersection with the X axis, you must substitute x=0 x=0 .

2

Step-by-step solution

To solve this problem, we need to determine whether substituting x=0 x = 0 gives us the points of intersection with the x-axis for the parabola y=(xp)2 y = (x - p)^2 .

To find the x-intercepts of any function, we set y=0 y = 0 because the x-intercepts occur where the curve meets the x-axis, which implies a zero output or function value:

  • Start with the equation: y=(xp)2 y = (x - p)^2 .
  • Set y=0 y = 0 for the x-intercept: (xp)2=0(x - p)^2 = 0.
  • Solving this gives (xp)=0(x - p) = 0 , which simplifies to x=p x = p .
  • Thus, the x-intercept happens at the point where x=p x = p , not where x=0 x = 0 .

Therefore, substituting x=0 x = 0 does not provide the x-intercepts. Instead, it provides the y-intercept. Therefore, the statement given in the problem is False.

Thus, the solution to the problem is False.

3

Final Answer

False

Practice Quiz

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Find the intersection of the function

\( y=(x-2)^2 \)

With the X

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