Identify Coefficients in y=-5+x²: Term-by-Term Analysis

Quadratic Coefficients with Standard Form

Identify the coefficients based on the following equation

y=5+x2 y=-5+x^2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the function coefficients
00:04 We'll use the formula for representing a quadratic equation
00:10 We'll arrange the equation to match the formula
00:35 We'll separate the unknown from the coefficient
00:48 We'll compare the formula to our equation and find the coefficients
01:00 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Identify the coefficients based on the following equation

y=5+x2 y=-5+x^2

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Express the equation in a standard quadratic form y=ax2+bx+c y = ax^2 + bx + c
  • Step 2: Identify the coefficients a a , b b , and the constant term c c by comparing the forms
  • Step 3: Select the corresponding answer choice based on the comparison

Now, let's work through each step:

Step 1: The given equation is y=5+x2 y = -5 + x^2 . We can rewrite this as y=x2+0x5 y = x^2 + 0x - 5 to match the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c .

Step 2: By comparing y=x2+0x5 y = x^2 + 0x - 5 directly with y=ax2+bx+c y = ax^2 + bx + c , we can identify:

  • The coefficient of x2 x^2 is a=1 a = 1 .
  • The coefficient of x x is b=0 b = 0 .
  • The constant term is c=5 c = -5 .

Step 3: Among the provided answer choices, we find that the parameters a=1 a = 1 , b=0 b = 0 , and c=5 c = -5 match the choice:

a=1,b=0,c=5 a = 1, b = 0, c = -5

Therefore, the solution to the problem is a=1,b=0,c=5 a = 1, b = 0, c = -5 .

3

Final Answer

a=1,b=0,c=5 a=1,b=0,c=-5

Key Points to Remember

Essential concepts to master this topic
  • Standard Form: Rewrite y=ax2+bx+c y = ax^2 + bx + c to identify coefficients
  • Technique: Convert y=5+x2 y = -5 + x^2 to y=x2+0x5 y = x^2 + 0x - 5
  • Check: Match term-by-term: a=1,b=0,c=5 a = 1, b = 0, c = -5

Common Mistakes

Avoid these frequent errors
  • Confusing coefficient order or missing zero coefficients
    Don't assume missing terms have coefficient 1 or forget zero coefficients = wrong identification! The x x term is missing, so b=0 b = 0 , not 1. Always rewrite in complete standard form ax2+bx+c ax^2 + bx + c first.

Practice Quiz

Test your knowledge with interactive questions

What is the value of the coefficient \( b \) in the equation below?

\( 3x^2+8x-5 \)

FAQ

Everything you need to know about this question

Why do I need to rewrite the equation in standard form first?

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Rewriting in standard form y=ax2+bx+c y = ax^2 + bx + c helps you see all terms clearly, including missing ones. This prevents you from accidentally assigning wrong coefficient values!

What does it mean when a term is missing from the equation?

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When a term like x x is missing, its coefficient is 0, not 1. In y=5+x2 y = -5 + x^2 , there's no x x term, so b=0 b = 0 .

How do I remember which coefficient is which?

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Think alphabetically: a a goes with x2 x^2 , b b goes with x x , and c c is the constant (no variable). The order matches: 2nd degree, 1st degree, 0 degree.

Can the coefficient of x² ever be negative?

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Yes! The coefficient a a can be any real number except 0. If a a is negative, the parabola opens downward instead of upward.

What if I can't tell which term goes where?

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Always arrange terms in descending order of powers: x2 x^2 term first, then x x term, then constant. This makes coefficient identification foolproof!

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