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Here we have a quadratic equation.
A quadratic equation is always constructed like this:
Where a, b, and c are generally already known to us, and the X and Y points need to be discovered.
Firstly, it seems that in this formula we do not have the C,
Therefore, we understand it is equal to 0.
a is the coefficient of X², here it does not have a coefficient, therefore
is the number that comes before the X that is not squared.
What is the value of the coefficient \( c \) in the equation below?
\( 4x^2+9x-2 \)
When no number appears before a variable, the coefficient is always 1. Think of as - the 1 is just invisible!
If there's no constant term (number without x), then c = 0. It's like saying you have 0 extra units. The equation is really .
a is the coefficient of (controls the parabola's width), b is the coefficient of (affects the vertex position), and c is the constant term (the y-intercept).
Yes! For example, has a=3, b=0, c=0. Missing terms just mean their coefficients are zero, but it's still a complete quadratic function.
Use alphabetical order! In , the letters a, b, c match the decreasing powers of x: x², x¹, x⁰ (which is just the constant).
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