Identify Terms in Sequence: Finding Values in an = 3n + 1

Arithmetic Sequences with Integer Position Validation

Given the series, y represents some term in the series and n represents the position of the term in the series.

Only one of the following is a term in the series, reveal it:

an=3n+1 a_n=3n+1

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find which of the following is a member of the sequence
00:04 We'll substitute this solution in the formula and solve for X
00:09 If the solution for X is positive and whole, then it's a member of the sequence
00:12 Let's isolate X
00:19 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Given the series, y represents some term in the series and n represents the position of the term in the series.

Only one of the following is a term in the series, reveal it:

an=3n+1 a_n=3n+1

2

Step-by-step solution

To solve this problem, we need to identify which of the given numbers is a term in the series defined by an=3n+1 a_n = 3n + 1 .

We will evaluate each choice:

  • Substitute 36: n=3613=353 n = \frac{36 - 1}{3} = \frac{35}{3} . This is not an integer, so 36 is not a term.
  • Substitute 39: n=3913=383 n = \frac{39 - 1}{3} = \frac{38}{3} . This is not an integer, so 39 is not a term.
  • Substitute 33: n=3313=323 n = \frac{33 - 1}{3} = \frac{32}{3} . This is not an integer, so 33 is not a term.
  • Substitute 40: n=4013=393=13 n = \frac{40 - 1}{3} = \frac{39}{3} = 13 . This is an integer, so 40 is a term.

Therefore, the number 40 is a term in the series.

40 40

3

Final Answer

40 40

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use an=3n+1 a_n = 3n + 1 to generate sequence terms
  • Technique: Solve n=value13 n = \frac{\text{value} - 1}{3} to check if value exists
  • Check: Position n must be a positive integer for valid term ✓

Common Mistakes

Avoid these frequent errors
  • Testing values without solving for n
    Don't just plug in random position numbers and calculate terms! This wastes time and misses the point. Always solve backwards: if a term equals some value, then n=value13 n = \frac{\text{value} - 1}{3} must give a positive integer.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

Why do I need to solve for n instead of just calculating terms?

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Because you're given potential terms and need to check if they belong to the sequence! Solving n=value13 n = \frac{\text{value} - 1}{3} tells you exactly which position (if any) would produce that term.

What if I get a decimal or fraction for n?

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Then that value is not a term in the sequence! Position numbers must be positive integers (1, 2, 3, 4...). Decimals like 11.67 mean the value falls between two actual terms.

How do I remember the backwards formula?

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Start with an=3n+1 a_n = 3n + 1 , then solve for n: subtract 1 from both sides, then divide by 3. So n=an13 n = \frac{a_n - 1}{3} !

Can I just calculate the first few terms to check?

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That's very inefficient! For large numbers like 40, you'd need to calculate many terms. The algebraic method gives you the answer instantly: n=4013=13 n = \frac{40-1}{3} = 13 .

What does it mean that 40 is the 13th term?

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It means when you substitute n=13 n = 13 into the formula, you get a13=3(13)+1=40 a_{13} = 3(13) + 1 = 40 . The 13th position in the sequence contains the value 40.

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