Solve for the Symmetrical Axis in the Quadratic f(x) = -2x² + 16

Quadratic Functions with Axis of Symmetry

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=2x2+16 f(x)=-2x^2+16

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:09 Let's find the axis of symmetry for this function.
00:12 The axis of symmetry is the X-value at the vertex of the parabola.
00:17 Imagine folding the parabola in half, both sides would match perfectly.
00:22 Let's examine the coefficients of the function.
00:30 We'll use the vertex formula to find the X-value.
00:35 Now, let's substitute the values we have and solve for X.
00:44 Great job! That's how we solve this problem.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=2x2+16 f(x)=-2x^2+16

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the coefficients a a and b b .
  • Step 2: Apply the symmetry axis formula.
  • Step 3: Simplify the expression to find the solution.

Now, let's work through each step:

Step 1: From the quadratic function f(x)=2x2+16 f(x) = -2x^2 + 16 , we identify the coefficients: a=2 a = -2 and b=0 b = 0 .

Step 2: Using the formula for the axis of symmetry, x=b2a x = -\frac{b}{2a} , we substitute the identified coefficients:

x=02(2) x = -\frac{0}{2(-2)} .

Step 3: Simplifying the expression, we have:

x=0 x = 0 .

Therefore, the solution to the problem is the axis of symmetry: x=0 x = 0 .

3

Final Answer

x=0 x=0

Key Points to Remember

Essential concepts to master this topic
  • Formula: Axis of symmetry is x = -b/(2a) for quadratic functions
  • Technique: From f(x) = -2x² + 16, identify a = -2, b = 0
  • Check: Substitute x = 0: f(0) = -2(0)² + 16 = 16 ✓

Common Mistakes

Avoid these frequent errors
  • Incorrectly identifying coefficient b
    Don't assume b equals the constant term 16 = wrong axis calculation! The term 16 has no x, so b = 0 in the standard form ax² + bx + c. Always identify coefficients in order: a (x² term), b (x term), c (constant).

Practice Quiz

Test your knowledge with interactive questions

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

\( f(x)=-3x^2+3 \)

FAQ

Everything you need to know about this question

Why is the coefficient b equal to 0 in this function?

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In f(x)=2x2+16 f(x) = -2x^2 + 16 , there's no x term (no middle term). The standard form is ax2+bx+c ax^2 + bx + c , so when there's no x term, b = 0.

What does the axis of symmetry tell me about the parabola?

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The axis of symmetry x=0 x = 0 means the parabola is perfectly balanced around the y-axis. Points on either side of x = 0 are mirror images of each other!

How can I verify that x = 0 is really the axis of symmetry?

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Check that points equidistant from x = 0 have the same y-value. For example: f(1)=2(1)2+16=14 f(1) = -2(1)^2 + 16 = 14 and f(1)=2(1)2+16=14 f(-1) = -2(-1)^2 + 16 = 14 . Same height!

What if I got a different answer like x = 8?

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Double-check your formula! Remember it's x=b2a x = -\frac{b}{2a} , not x=c2a x = -\frac{c}{2a} . The constant term 16 is c, not b. Since b = 0, the axis is at x = 0.

Does every quadratic function have an axis of symmetry?

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Yes, absolutely! Every parabola has exactly one axis of symmetry. It's a vertical line that passes through the vertex (highest or lowest point) of the parabola.

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