Solve for the Symmetrical Axis in the Quadratic f(x) = -2x² + 16

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=2x2+16 f(x)=-2x^2+16

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:13 Let's examine the function's coefficients
00:21 We'll use the formula to calculate the vertex point
00:26 We'll substitute appropriate values according to the given data and solve for X at the point
00:35 And this is the solution to the problem

Step-by-step written solution

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1

Understand the problem

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=2x2+16 f(x)=-2x^2+16

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the coefficients a a and b b .
  • Step 2: Apply the symmetry axis formula.
  • Step 3: Simplify the expression to find the solution.

Now, let's work through each step:

Step 1: From the quadratic function f(x)=2x2+16 f(x) = -2x^2 + 16 , we identify the coefficients: a=2 a = -2 and b=0 b = 0 .

Step 2: Using the formula for the axis of symmetry, x=b2a x = -\frac{b}{2a} , we substitute the identified coefficients:

x=02(2) x = -\frac{0}{2(-2)} .

Step 3: Simplifying the expression, we have:

x=0 x = 0 .

Therefore, the solution to the problem is the axis of symmetry: x=0 x = 0 .

3

Final Answer

x=0 x=0

Practice Quiz

Test your knowledge with interactive questions

Given the expression of the quadratic function

Finding the symmetry point of the function

\( f(x)=-5x^2+10 \)

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