Solve for the Symmetrical Axis in the Quadratic f(x) = -2x² + 16

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

$f(x)=-2x^2+16$

Video Solution

Solution Steps

00:00 Find the axis of symmetry for the function

00:03 The axis of symmetry is the X value at the vertex point

00:06 The point where if you fold the parabola in half, both halves are identical

00:13 Let's examine the function's coefficients

00:21 We'll use the formula to calculate the vertex point

00:26 We'll substitute appropriate values according to the given data and solve for X at the point

00:35 And this is the solution to the problem

Step-by-Step Solution

To solve this problem, we'll follow these steps:

Now, let's work through each step:

Step 1: From the quadratic function $f(x) = -2x^2 + 16$ , we identify the coefficients: $a = -2$ and $b = 0$ .

Step 2: Using the formula for the axis of symmetry, $x = -\frac{b}{2a}$ , we substitute the identified coefficients:

$x = -\frac{0}{2(-2)}$ .

Step 3: Simplifying the expression, we have:

$x = 0$ .

Therefore, the solution to the problem is the axis of symmetry: $x = 0$ .