Identifying Applications of the Rational Expression 3/(x+2)

Identify the field of application of the following fraction:

3x+2 \frac{3}{x+2}

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Step-by-step video solution

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00:00 Find the domain of assignment
00:03 Assignment domain exists, to ensure we don't divide by 0
00:06 Meaning the denominator in the fraction must be different from 0
00:09 We will use this formula in our exercise
00:12 We will isolate X to find the domain of assignment
00:26 This is the domain of assignment, and this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Identify the field of application of the following fraction:

3x+2 \frac{3}{x+2}

2

Step-by-step solution

Let's examine the given expression:

3x+2 \frac{3}{x+2}

As we know, the only restriction that applies to division is division by 0, since no number can be divided into 0 parts. Hence division by 0 is undefined.

Therefore, when we talk about a fraction, where the dividend (the number being divided) is in the numerator, and the divisor (the number we divide by) is in the denominator, the restriction applies only to the denominator, which must be different from 0,

In the given expression:

3x+2 \frac{3}{x+2}

As stated, the restriction applies to the fraction's denominator only,

Therefore, in order for the given expression (the fraction - in this case) to be defined, we require that the expression in its denominator - does not equal zero, meaning we require that:

x+20 x+2\neq0

We will solve this inequality, which is a point inequality of first degree, in the same way we solve a first-degree equation, meaning - we isolate the variable on one side, by moving terms (and dividing both sides of the inequality by its coefficient if needed):

x+20x2 x+2\neq0 \\ \boxed{x\neq -2}

Therefore, the domain (definition domain) of the given expression is:

x2 x\neq -2

(This means that if we substitute for the variable x any number different from(2) (-2) the expression will remain well-defined),

Therefore, the correct answer is answer D.

Note:

In general - solving an inequality of this form, meaning, a non-linear, but point inequality - that uses the \neq sign and not the inequality signs: ,>,<,,, ,>,\hspace{2pt}<,\hspace{2pt}\geq,\hspace{2pt}\leq,\hspace{2pt} is identical in every aspect to an equation and therefore is solved in the same way and all rules used to solve an equation of any type are identical for it as well.

3

Final Answer

x2 x\neq-2

Practice Quiz

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Determine if the simplification below is correct:

\( \frac{4\cdot8}{4}=\frac{1}{8} \)

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