Multiplication and Division of Algebraic Fractions

πŸ†Practice factorization and algebraic fractions

Multiplication and Division Operations in Algebraic Fractions

When we want to multiply or divide algebraic fractions, we will use the same tools that we use for the multiplication or division of common fractions with some small differences.

Steps to carry out for the multiplication of algebraic fractions 1 1 :

  • Let's try to extract the common factor.
    This can be the variable or any free number.
  • If this is not enough, we will factorize with short multiplication formulas or with trinomials.
  • Let's find the solution set.
    • How is the solution set found?
      We will make all the denominators we have equal to 0 0 and find the solution.
      The solution set will be X X : different from what causes our denominator to equal zero.
  • Let's simplify the fractions with determination.
  • Multiply numerator by numerator and denominator by denominator as in any fraction.
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Test yourself on factorization and algebraic fractions!

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Select the field of application of the following fraction:

\( \frac{7}{13+x} \)

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Steps to carry out for the division of algebraic fractions 2 2 :

  • We will convert the division exercise into a multiplication one, as we do with common fractions.
    How will we do it correctly?
    We will leave the first fraction as it is, change the division sign to a multiplication sign, and invert the fraction that appears after the sign. That is, numerator instead of denominator and denominator instead of numerator.
  • We will act according to the rules of multiplication of algebraic fractions:
    • Let's try to extract the common factor.
      This can be the unknown or any free number.
    • If this is not enough, we will factorize using short multiplication formulas and with trinomials.
    • Let's find the solution set.
      • How is the solution set found?
        We will make all the denominators we have equal to 0 0 and find the solution.
        The solution set will be X X : different from what causes our denominator to equal zero.
    • Let's simplify the fractions with determination.
    • Multiply numerator by numerator and denominator by denominator as in any fraction.

Let's look at an example of multiplying algebraic fractions

x+2x+3Γ—3x+9x2βˆ’4=\frac{x+2}{x+3}\times \frac{3x+9}{x^2-4}=

Let's try to factorize by extracting the common factor and with the shortcut multiplication formulas, and we will obtain:
x+2x+3Γ—3(x+3)(xβˆ’2)(x+2=\frac{x+2}{x+3}\times \frac{3(x+3)}{(x-2)(x+2}=

Let's find the solution set:

xβ‰ βˆ’3,2,βˆ’2xβ‰ -3,2,-2

Let's reduce the fractions and we will obtain:

Let's see an example of multiplying algebraic fractions

1Γ—3(xβˆ’2)=1\times \frac{3}{(x-2)}=
Multiply and it will give us:
3xβˆ’2\frac{3}{x-2}


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Example of Division of Algebraic Fractions

x2βˆ’8x+15x2βˆ’3x+2:x2βˆ’9xβˆ’1=\frac{x^2-8x+15}{x^2-3x+2}:\frac{x^2-9}{x-1}=

Let's convert the division exercise into a multiplication one:

x2βˆ’8x+15x2βˆ’3x+2Γ—xβˆ’1x2βˆ’9=\frac{x^2-8x+15}{x^2-3x+2}\times \frac{x-1}{x^{2-9}}=
Now, let's factor and we will get:
(xβˆ’5)(xβˆ’3)(xβˆ’2)(xβˆ’1)Γ—xβˆ’1(xβˆ’3)(x+3)=\frac{(x-5)(x-3)}{(x-2)(x-1)}\times \frac{x-1}{(x-3)(x+3)}=
Let's find the solution set:
xβ‰ 2,1,3,βˆ’3xβ‰ 2,1,3,-3

Let's simplify, we will get:

Example of algebraic fractions division

xβˆ’5xβˆ’2Γ—1x+3\frac{x-5}{x-2}\times \frac{1}{x+3}

Let's multiply and it will give us:
xβˆ’5(xβˆ’2)(x+3)\frac{x-5}{(x-2)(x+3)}



If you are interested in this article, you might also be interested in the following articles:

  • The uses of factorization
  • Factorization according to short multiplication formulas
  • Factorization through the extraction of the common factor outside the parentheses
  • Factorization of trinomials
  • Factorization of algebraic fractions
  • Addition and subtraction of algebraic fractions
  • Simplification of algebraic fractions
  • Solving equations through factorization

In the Tutorela blog, you will find a variety of articles about mathematics.


Examples and exercises with solutions for multiplication and division of algebraic fractions

examples.example_title

Determine if the simplification described here is true or false:

6β‹…36β‹…3=1 \frac{6\cdot3}{6\cdot3}=1

examples.explanation_title

We simplify the expression on the left side of the approximate equality:

6ΜΈβ‹…3ΜΈ6ΜΈβ‹…3ΜΈ=?1↓1=!1 \frac{\textcolor{red}{\not{6}}\cdot\textcolor{blue}{\not{3}}}{\textcolor{red}{\not{6}}\cdot\textcolor{blue}{\not{3}}}\stackrel{?}{= }1\\ \downarrow\\ 1\stackrel{!}{= }1 therefore, the described reduction is correct.

Therefore, the correct answer is option A.

examples.solution_title

True

examples.example_title

Determine if the simplification described here is true or false:

5β‹…88β‹…3=53 \frac{5\cdot8}{8\cdot3}=\frac{5}{3}

examples.explanation_title

Let's consider the fraction and break it down into two multiplication exercises:

88Γ—53 \frac{8}{8}\times\frac{5}{3}

We simplify:

1Γ—53=53 1\times\frac{5}{3}=\frac{5}{3}

examples.solution_title

True

examples.example_title

Determine if the simplification described here is true or false:

4β‹…84=18 \frac{4\cdot8}{4}=\frac{1}{8}

examples.explanation_title

We will divide the fraction exercise into two multiplication exercises:

44Γ—81= \frac{4}{4}\times\frac{8}{1}=

We simplify:

1Γ—81=8 1\times\frac{8}{1}=8

Therefore, the described simplification is false.

examples.solution_title

False

examples.example_title

Determine if the simplification described here is true or false:

3β‹…77β‹…3=0 \frac{3\cdot7}{7\cdot3}=0

examples.explanation_title

We will divide the fraction exercise into two different multiplication exercises,
As this is a multiplication exercise, you can use the substitution property:

77Γ—33=1Γ—1=1 \frac{7}{7}\times\frac{3}{3}=1\times1=1

Therefore, the simplification described is false.

examples.solution_title

False

examples.example_title

Determine if the simplification described here is true or false:

77β‹…8=8 \frac{7}{7\cdot8}=8

examples.explanation_title

Let's consider the fraction and break it down into two multiplication exercises:

77Γ—18 \frac{7}{7}\times\frac{1}{8}

We simplify:

1Γ—18=18 1\times\frac{1}{8}=\frac{1}{8}

Therefore, the described simplification is false.

examples.solution_title

False

Do you know what the answer is?
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