Long Division Problem: Divide 20035 by 6 Step-by-Step

Long Division with Five-Digit Dividends

620035

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:04 Let's start by dividing the leftmost digit in the dividend
00:07 2 is less than 6, so we'll bring down the next digit, and then divide
00:11 Write the result without remainder above, paying attention to position
00:15 Now multiply the result by the divisor
00:19 Subtract the product from the number
00:24 Now bring down the next digit and use the same steps
00:29 We got the same number, so we'll use the same calculations
00:35 Now bring down the next digit and use the same steps
00:42 Divide
00:46 Write the result without remainder above, paying attention to position
00:50 Multiply the result and subtract
00:55 Now bring down the next digit and use the same steps
00:59 Divide
01:03 Write the result without remainder above, paying attention to position
01:09 Multiply the result and subtract
01:15 We got a remainder of 1
01:19 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

620035

2

Step-by-step solution

To solve this problem, we'll perform long division of 20035 by 6:

  • Step 1: Divide 20 by 6.
    - 6 goes into 20 three times (since 6×3=18 6 \times 3 = 18 ), leaving a remainder of 2.
    - Write the 3 in the quotient, and bring down the next digit, 0, to make 20.
  • Step 2: Divide 20 by 6 again.
    - 6 goes into 20 three times (same calculation as before), leaving a remainder of 2.
    - Write the next 3 in the quotient, and bring down the next digit, 0, to make 23.
  • Step 3: Divide 23 by 6.
    - 6 fits into 23 three times (since 6×3=18 6 \times 3 = 18 ), leaving a remainder of 5.
    - Write the next 3 in the quotient, and bring down the next digit, 5, to make 55.
  • Step 4: Divide 55 by 6.
    - 6 fits into 55 nine times (since 6×9=54 6 \times 9 = 54 ), leaving a remainder of 1.

The resultant quotient is 3339, with a remainder of 1.

Therefore, the solution to the problem is 3339 3339 with a remainder of 1.

3

Final Answer

3339 3339 with a remainder of 1

Key Points to Remember

Essential concepts to master this topic
  • Rule: Start dividing from the leftmost digits of the dividend
  • Technique: 6 goes into 20 three times (6×3=18), remainder 2
  • Check: Multiply quotient by divisor and add remainder: 3339×6+1=20035 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to bring down digits systematically
    Don't skip bringing down the next digit after each division step = incomplete calculations! This leads to wrong quotient values and missing remainder. Always bring down one digit at a time and complete each division step fully.

Practice Quiz

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216

FAQ

Everything you need to know about this question

Why do I start with 20 instead of just 2?

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You need enough digits to divide! Since 6 is larger than 2, you can't divide 2 by 6. Take the first two digits (20) to get a number large enough for division.

What happens if I can't divide evenly?

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That's normal in long division! The remainder is what's left over. In this problem, 20035 ÷ 6 = 3339 with remainder 1, meaning 1 is left over after all divisions.

How do I know when to stop dividing?

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Stop when you've brought down all digits from the dividend and completed the final division. The last remainder becomes your final remainder for the answer.

Why does 6 go into 23 only 3 times when 6×4=24?

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Because 6×4=24 is greater than 23! In division, you use the largest whole number that doesn't exceed your dividend. Since 6×3=18 ≤ 23 but 6×4=24 > 23, use 3.

How can I check if my long division is correct?

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  • Multiply: quotient × divisor
  • Add: the remainder
  • Compare: result should equal original dividend
  • Example: 3339×6+1=20035 3339 \times 6 + 1 = 20035

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