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To solve this problem, we'll perform long division of 20035 by 6:
The resultant quotient is 3339, with a remainder of 1.
Therefore, the solution to the problem is with a remainder of 1.
with a remainder of 1
You need enough digits to divide! Since 6 is larger than 2, you can't divide 2 by 6. Take the first two digits (20) to get a number large enough for division.
That's normal in long division! The remainder is what's left over. In this problem, 20035 ÷ 6 = 3339 with remainder 1, meaning 1 is left over after all divisions.
Stop when you've brought down all digits from the dividend and completed the final division. The last remainder becomes your final remainder for the answer.
Because 6×4=24 is greater than 23! In division, you use the largest whole number that doesn't exceed your dividend. Since 6×3=18 ≤ 23 but 6×4=24 > 23, use 3.
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