Long Division Problem: Divide 20035 by 6 Step-by-Step

To solve this problem, we'll perform long division of 20035 by 6:

• Step 1: Divide 20 by 6.
  - 6 goes into 20 three times (since $6 \times 3 = 18$), leaving a remainder of 2.
  - Write the 3 in the quotient, and bring down the next digit, 0, to make 20.
• Step 2: Divide 20 by 6 again.
  - 6 goes into 20 three times (same calculation as before), leaving a remainder of 2.
  - Write the next 3 in the quotient, and bring down the next digit, 0, to make 23.
• Step 3: Divide 23 by 6.
  - 6 fits into 23 three times (since $6 \times 3 = 18$), leaving a remainder of 5.
  - Write the next 3 in the quotient, and bring down the next digit, 5, to make 55.
• Step 4: Divide 55 by 6.
  - 6 fits into 55 nine times (since $6 \times 9 = 54$), leaving a remainder of 1.

The resultant quotient is 3339, with a remainder of 1.

Therefore, the solution to the problem is $3339$ with a remainder of 1.