We have hundreds of course questions with personalized recommendations + Account 100% premium
To solve this problem, we'll conduct a long division of 325 by 14 step by step:
The quotient of is with a remainder of .
Therefore, the solution to the problem is with a remainder of .
with a remainder of 3
Since 14 is larger than 3, it can't fit even once! That's why we look at the first two digits (32) instead. Always use enough digits so your divisor fits at least once.
Try multiples until you find the largest one that doesn't exceed your number. For 32: fits, but is too big!
Always double-check your multiplication tables! Write them out if needed: , , , etc.
Multiply your quotient by the divisor, then add the remainder: . If this equals your original dividend (325), you're right!
The remainder is what's left over after division. It means 325 contains exactly 23 groups of 14, plus 3 extra that can't form another complete group.
Never! If your remainder equals or exceeds the divisor, you can divide at least one more time. The remainder must always be smaller than what you're dividing by.
Get unlimited access to all 18 Arithmetic Operations questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime