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To solve this problem using long division, we will follow these steps:
Let's perform the division:
Step 1: Take the first digit of 5111, which is 5. Since 5 is less than 11, look at the first two digits, 51.
Step 2: Divide 51 by 11. The result is 4 (since ), with a remainder of 7.
Subtract 44 from 51, we get 7. Bring down the next digit, 1, making the number 71.
Step 3: Divide 71 by 11, which is 6 (since ), with a remainder of 5.
Subtract 66 from 71, we get 5. Bring down the next digit, 1, making the number 51.
Step 4: Divide 51 by 11, which is 4 again, with a remainder of 7 (since ). There are no more digits to bring down.
The quotient from dividing 5111 by 11 is therefore 464 with a remainder of 7.
Therefore, the solution to the problem is with a remainder of 7.
with a remainder of 7
Since 5 is smaller than 11, we can't divide it evenly. We need to look at the first two digits (51) to get a number that's greater than or equal to our divisor!
Ask yourself: "What's the largest number I can multiply 11 by without going over my target?" For 71, that's 6 because but is too big.
Write down each step clearly! When you subtract and get a remainder, that remainder becomes the first digit of your next number when you bring down the next digit.
Use this formula: Dividend = (Quotient × Divisor) + Remainder
For our problem: ✓
The remainder must always be smaller than the divisor! Since we're dividing by 11, any remainder must be between 0 and 10. A remainder of 7 means we have 7 left over that can't be divided by 11.
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