Match Equivalent Expressions: (a±b)(c±4) Expansions

Question

Join expressions of equal value

$(a-b)(c-4)$
$(a+b)(c+4)$
$(a-b)(c+4)$
$(a+b)(c-4)$
a. $ac-4a+bc-4b$
b. $ac+4a-bc-4b$
c. $ac-4a-bc+4b$
d. $ac+4a+bc+4b$

00:00 Open brackets

00:03 Open brackets properly, multiply each factor by each factor

00:14 Calculate the multiplications, and group the factors

00:21 This is the simplification for 1, let's continue to 2

00:27 Open brackets properly, multiply each factor by each factor

00:32 Calculate the multiplications, and group the factors

00:38 This is the simplification for 2, let's continue to 3

00:42 Open brackets properly, multiply each factor by each factor

00:50 Calculate the multiplications, and group the factors

00:53 This is the simplification for 3, let's continue to 4

01:00 Open brackets properly, multiply each factor by each factor

01:03 Calculate the multiplications, and group the factors

01:10 And this is the solution to the question

We use all the exercises of the extended distributive property: $(a+b)\times(c+d)=ac+ad+bc+bd$

1. $(a-b)(c-4)=ac-4a-bc+4b$

2. $(a+b)(c+4)=ac+4a+bc+4b$

3. $(a-b)(c+4)=ac+4a-bc-4b$

4. $(a+b)(c-4)=ac-4a+bc-4b$

1-c, 2-d, 3-b, 4-a