Match Expressions: (-7-x)(a-13) and Its Equivalent Forms

Polynomial Expansion with Algebraic Matching

Join expressions of equal value

  1. (7x)(a13) (-7-x)(a-13)

  2. (a+13)(7x) (-a+13)(-7-x)

  3. (7+x)(a13) (7+x)(a-13)

    a.7a+ax9113x 7a+ax-91-13x

    b.7a+91ax+13x -7a+91-ax+13x

    c.7aax+9113x 7a-ax+91-13x

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Open parentheses
00:04 Let's open parentheses properly, multiply each factor by each factor
00:21 Calculate the products and collect terms
00:28 This is the simplification for 1, let's continue to 2
00:38 Let's open parentheses properly, multiply each factor by each factor
00:46 Calculate the products and collect terms
00:52 This is the simplification for 2, let's continue to 3
01:00 Let's open parentheses properly, multiply each factor by each factor
01:05 Calculate the products and collect terms
01:13 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Join expressions of equal value

  1. (7x)(a13) (-7-x)(a-13)

  2. (a+13)(7x) (-a+13)(-7-x)

  3. (7+x)(a13) (7+x)(a-13)

    a.7a+ax9113x 7a+ax-91-13x

    b.7a+91ax+13x -7a+91-ax+13x

    c.7aax+9113x 7a-ax+91-13x

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Expand each given expression using the distributive property.
  • Step 2: Simplify the expressions obtained from expansion.
  • Step 3: Compare the simplified expressions to the given expanded forms (a, b, and c).
  • Step 4: Determine which expanded forms correspond to which original expressions and select the correct answer choice.

Let's begin with Step 1:
Expression 1: (7x)(a13)(-7-x)(a-13)

Expand:
(7)(a)+(7)(13)+(x)(a)+(x)(13)(-7)(a) + (-7)(-13) + (-x)(a) + (-x)(-13) = 7a+91ax+13x-7a + 91 - ax + 13x

Expression 2: (a+13)(7x)(-a+13)(-7-x)

Expand:
(a)(7)+(a)(x)+13(7)+13(x)(-a)(-7) + (-a)(-x) + 13(-7) + 13(-x) = 7a+ax9113x7a + ax - 91 - 13x

Expression 3: (7+x)(a13)(7+x)(a-13)

Expand:
7a91+ax13x7a - 91 + ax - 13x

Now proceed with Step 3: Comparing these expanded expressions to the provided forms:

  • Expression 1: 7a+91ax+13x-7a + 91 - ax + 13x corresponds with Form b: 7a+91ax+13x-7a + 91 - ax + 13x.
  • Expression 2: 7a+ax9113x7a + ax - 91 - 13x matches with Form a: 7a+ax9113x7a + ax - 91 - 13x.
  • Expression 3: 7a91+ax13x7a - 91 + ax - 13x is equivalent to Form a: 7a+ax9113x7a + ax - 91 - 13x after rearranging terms.

After comparing, we obtain the answer selection as 1-b, 2,3-a.

3

Final Answer

1-b, 2,3-a

Key Points to Remember

Essential concepts to master this topic
  • Distributive Property: Multiply each term in first bracket by every term in second
  • Technique: (7x)(a13)=7a+91ax+13x(-7-x)(a-13) = -7a + 91 - ax + 13x using FOIL method
  • Check: Compare expanded forms term by term to match coefficients ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute negative signs correctly
    Don't treat (7x)(a13)(-7-x)(a-13) as (7+x)(a13)(7+x)(a-13) = wrong signs throughout! Negative signs must be distributed to every term they multiply. Always track negative signs carefully when expanding brackets.

Practice Quiz

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\( (x+y)(x-y)= \)

FAQ

Everything you need to know about this question

Why do I get different arrangements of the same terms?

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Addition is commutative, so 7a+ax9113x7a + ax - 91 - 13x equals 7a91+ax13x7a - 91 + ax - 13x. The order doesn't matter as long as the signs are correct!

How do I know which expression matches which expanded form?

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Expand each expression completely, then rearrange terms to match the given forms. Look for identical coefficients and signs in the same positions.

What if I get confused with all the negative signs?

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Take it step by step! Use the distributive property carefully: (7x)(a13)=(7)(a)+(7)(13)+(x)(a)+(x)(13)(-7-x)(a-13) = (-7)(a) + (-7)(-13) + (-x)(a) + (-x)(-13). Write out every multiplication before combining.

Can expressions with different orders be equivalent?

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Yes! 7a+ax9113x7a + ax - 91 - 13x and 7a91+ax13x7a - 91 + ax - 13x are the same because addition allows us to rearrange terms without changing the value.

How do I check my expansion is correct?

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Substitute simple values like a=1,x=1a=1, x=1 into both the original and expanded forms. If they give the same result, your expansion is likely correct!

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