Matching Expressions: Group (b+c)(a-4) and Similar Polynomial Products

Group the expressions that have the same value.

  1. (b+c)(a4) (b+c)(a-4)

  2. (4+c)(a+b) (4+c)(a+b)

  3. (a+4)(bc) (a+4)(b-c)

  4. (b+4)(ca) (b+4)(c-a)

    a. ac+ab4b4c ac+ab-4b-4c

    b. 4b+ab4cac 4b+ab-4c-ac

    c. bcab+4c4a bc-ab+4c-4a

    d. 4a+4b+ac+cb 4a+4b+ac+cb

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:02 Simplify each expression
00:11 Let's calculate the products
00:54 Open parentheses properly, multiply each factor by each factor
01:02 Let's calculate the products
01:08 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Group the expressions that have the same value.

  1. (b+c)(a4) (b+c)(a-4)

  2. (4+c)(a+b) (4+c)(a+b)

  3. (a+4)(bc) (a+4)(b-c)

  4. (b+4)(ca) (b+4)(c-a)

    a. ac+ab4b4c ac+ab-4b-4c

    b. 4b+ab4cac 4b+ab-4c-ac

    c. bcab+4c4a bc-ab+4c-4a

    d. 4a+4b+ac+cb 4a+4b+ac+cb

2

Step-by-step solution

To solve this problem, we need to expand each given algebraic expression using the distributive property and match each expanded form with the given standard forms. Let’s go through each expression:

Expression 1: (b+c)(a4) (b+c)(a-4)

  • Apply distributive property: ba4b+ca4c ba - 4b + ca - 4c
  • Combine like terms, resulting in: ab+ac4b4c ab + ac - 4b - 4c .
  • This matches with option a: ac+ab4b4c ac + ab - 4b - 4c .

Expression 2: (4+c)(a+b) (4+c)(a+b)

  • Apply distributive property: 4a+4b+ca+cb 4a + 4b + ca + cb
  • Combine like terms, resulting in: 4a+4b+ac+cb 4a + 4b + ac + cb .
  • This matches with option d: 4a+4b+ac+cb 4a + 4b + ac + cb .

Expression 3: (a+4)(bc) (a+4)(b-c)

  • Apply distributive property: abac+4b4c ab - ac + 4b - 4c
  • Combine like terms, resulting in: abac+4b4c ab - ac + 4b - 4c .
  • This matches with option b: 4b+ab4cac 4b + ab - 4c - ac .

Expression 4: (b+4)(ca) (b+4)(c-a)

  • Apply distributive property: bcba+4c4a bc - ba + 4c - 4a
  • Combine like terms, resulting in: bcab+4c4a bc - ab + 4c - 4a .
  • This matches with option c: bcab+4c4a bc - ab + 4c - 4a .

Grouping the results, we have:

  • 1 matches with a.
  • 2 matches with d.
  • 3 matches with b.
  • 4 matches with c.

Therefore, the solution to the problem is 1-a, 2-d, 3-b, 4-c.

3

Final Answer

1-a, 2-d, 3-b, 4-c

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\( (3+20)\times(12+4)= \)

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