Rearranged the following numbers to make a number divisible by 10:
5, 1 ,0, and 2.
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Rearranged the following numbers to make a number divisible by 10:
5, 1 ,0, and 2.
To solve this problem, we should organize the given digits to make a number that is divisible by 10. According to the rule of divisibility by 10, a number must end in 0.
Let's follow these steps:
The number 5210 ends with 0, making it divisible by 10.
Therefore, the solution to the problem is .
5120
Is the number 43 divisible by 4?
The divisibility rule for 10 states that any number ending in 0 is divisible by 10. This is because 10 = 2 × 5, and ending in 0 guarantees the number has factors of both 2 and 5.
For the smallest number divisible by 10, place 0 at the end and arrange the remaining digits in ascending order. With digits 5,1,2,0, the smallest would be 1250.
Never start with 0! Numbers cannot begin with 0 (like 0521) because that would make it a 3-digit number, not a 4-digit number using all given digits.
After placing 0 at the end, arrange the remaining digits based on what you want: largest number = descending order (5,2,1), smallest number = ascending order (1,2,5).
Yes! Any arrangement of 5,1,2 followed by 0 works:
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