Rearrange the Digits 2, 3, and 5 to Create a Number Divisible by 10

Divisibility Rules with Missing Digits

Rearrange the following digits to create a number divisible by 10:

2, 3 , and 5.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Compose a number that is divisible by 10
00:04 A number divisible by 10 is a number with units digit 0
00:07 Using this method, we will go through all numbers and eliminate accordingly
00:16 We can see there is no suitable number, and this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Rearrange the following digits to create a number divisible by 10:

2, 3 , and 5.

2

Step-by-step solution

To solve this problem, we need to understand the divisibility rule for 1010. A number is divisible by 1010 if and only if it ends in 00.

Given the digits 22, 33, and 55, we need to form a number ending with 00. However, none of these digits is 00. Therefore, using only the digits 22, 33, and 55, it is impossible to create a number that ends in 00.

This means it's impossible to rearrange these digits to form a number divisible by 1010.

Therefore, the correct answer is It is impossible.

3

Final Answer

It is impossible.

Key Points to Remember

Essential concepts to master this topic
  • Rule: Numbers divisible by 10 must end in 0
  • Technique: Check if digit 0 exists in given set: 2, 3, 5
  • Check: No 0 available means no valid arrangement possible ✓

Common Mistakes

Avoid these frequent errors
  • Testing all possible arrangements without checking divisibility rule first
    Don't try arranging 235, 253, 325, 352, 523, 532 and testing each = wasted time! This ignores the fundamental rule. Always check if the required ending digit (0 for divisibility by 10) is available first.

Practice Quiz

Test your knowledge with interactive questions

Is the number 10 divisible by 4?

FAQ

Everything you need to know about this question

Why can't I just put 5 at the end since 5 divides into 10?

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Great thinking, but divisibility by 1010 requires the number to end in 0, not 55. Numbers ending in 55 are divisible by 55, but not by 1010.

What if the question asked about divisibility by 5 instead?

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Then we could solve it! Numbers divisible by 55 must end in 00 or 55. Since we have the digit 55, arrangements like 235 and 325 would work.

Are there other digits that would make this impossible?

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Yes! If you need a number divisible by 1010 but don't have the digit 00, it's always impossible. The divisibility rule for 1010 is non-negotiable.

How do I quickly recognize when a rearrangement problem is impossible?

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Check the divisibility rule first! For divisibility by 1010, you need 00. For even numbers, you need 0,2,4,6,0, 2, 4, 6, or 88 at the end. No required digit = impossible!

Could I add a 0 to make this work?

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Only if the problem allows it! This question specifically says to use only the digits 2,3,2, 3, and 55. Adding extra digits would change the problem entirely.

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