Rearrange the following digits to create a number divisible by 10:
2, 3 , and 5.
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Rearrange the following digits to create a number divisible by 10:
2, 3 , and 5.
To solve this problem, we need to understand the divisibility rule for . A number is divisible by if and only if it ends in .
Given the digits , , and , we need to form a number ending with . However, none of these digits is . Therefore, using only the digits , , and , it is impossible to create a number that ends in .
This means it's impossible to rearrange these digits to form a number divisible by .
Therefore, the correct answer is It is impossible.
It is impossible.
Is the number 10 divisible by 4?
Great thinking, but divisibility by requires the number to end in 0, not . Numbers ending in are divisible by , but not by .
Then we could solve it! Numbers divisible by must end in or . Since we have the digit , arrangements like 235 and 325 would work.
Yes! If you need a number divisible by but don't have the digit , it's always impossible. The divisibility rule for is non-negotiable.
Check the divisibility rule first! For divisibility by , you need . For even numbers, you need or at the end. No required digit = impossible!
Only if the problem allows it! This question specifically says to use only the digits and . Adding extra digits would change the problem entirely.
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