Rectangle Perimeter Problem: Finding X When Perimeter = 28 and Width = 11

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information
• Step 2: Use the perimeter formula
• Step 3: Solve for $x$

Now, let's work through each step:

Step 1: The problem gives us that the perimeter of the rectangle is 28, one side (length) is 11, and the other side (width) is $x$.
Step 2: We'll use the formula for the perimeter of a rectangle: $P = 2(l + w)$. In this problem, $l = 11$ and $w = x$ so:

$28 = 2(11 + x)$

Step 3: Divide both sides by 2 to isolate the expression inside the parentheses:

$14 = 11 + x$

Step 4: Subtract 11 from both sides to solve for $x$:

$x = 14 - 11 = 3$

Therefore, the value of $x$ is $3$.