Reduce (5²×2³×3)³×3² ÷ (2⁴×5³): Complex Exponential Expression

Question

Reduce the following equation:

(52×23×3)3×3224×53= \frac{\left(5^2\times2^3\times3\right)^3\times3^2}{2^4\times5^3}=

Video Solution

Solution Steps

00:00 Simply
00:02 any number to the power of 1 equals itself
00:05 we will use this formula in our exercise
00:09 let's open the parentheses and raise each factor to its power
00:32 we'll use the formula for power of a power
00:35 any number (A) to the power of (M) to the power of (N)
00:38 equals the same number (A) to the power of the product of exponents (M*N)
00:44 we will use this formula in our exercise
00:47 we'll keep the bases and multiply the exponents
01:04 let's calculate the products
01:59 let's break down the fraction into a fraction and product
02:07 we'll use the formula for multiplication of powers
02:10 any number (A) to the power of (M) multiplied by the same number (A) to the power of (N)
02:13 equals the same number (A) to the power of the sum of exponents (M+N)
02:16 we will use this formula in our exercise
02:24 we'll keep the bases and add the exponents
02:39 let's calculate the sum
03:10 let's break down the fraction into 2 fractions with equal bases
03:22 we'll use the formula for division of powers
03:25 any division of powers with the same base (A) and different exponents
03:28 equals the same base (A) to the power of the difference of exponents (M-N)
03:32 we will use this formula in our exercise
03:35 we'll keep the bases and subtract the exponents

Step-by-Step Solution

Let's reduce the given expression step-by-step using the laws of exponents.

The expression to simplify is:

(52×23×3)3×3224×53\frac{\left(5^2\times2^3\times3\right)^3\times3^2}{2^4\times5^3}

First, simplify the expression inside the bracket:

  • Apply the power of a power rule (am)n=am×n(a^m)^n = a^{m \times n} to each term:

    • (52)3=52×3=56(5^2)^3 = 5^{2 \times 3} = 5^6

    • (23)3=23×3=29(2^3)^3 = 2^{3 \times 3} = 2^9

    • (31)3=31×3=33(3^1)^3 = 3^{1 \times 3} = 3^3

  • Substitute back into the expression:

  • 56×29×33×3224×53\frac{5^6 \times 2^9 \times 3^3 \times 3^2}{2^4 \times 5^3}

Next, combine the powers in the numerator:

  • Use the product of powers rule am×an=am+na^m \times a^n = a^{m+n}:

    • Combine the 3s: 33×32=33+2=353^3 \times 3^2 = 3^{3+2} = 3^5

  • The refined numerator is 56×29×355^6 \times 2^9 \times 3^5.

Now, simplify the fraction using division of powers:

  • For 5's: 5653=563=53\frac{5^6}{5^3} = 5^{6-3} = 5^3

  • For 2's: 2924=294=25\frac{2^9}{2^4} = 2^{9-4} = 2^5

  • 3's remain 353^5, as they only appear in the numerator.

Therefore, the final expression is:

53×25×35\boxed{5^3 \times 2^5 \times 3^5}

Answer

53×25×35 5^3\times2^5\times3^5