Simplify (x³)² × y⁵/y³: Step-by-Step Exponent Reduction

Exponent Rules with Power Operations

Reduce the following equation:

(x3)2×y5y3= \frac{\left(x^3\right)^2\times y^5}{y^3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's begin by simplifying the problem.
00:15 We'll break the fraction into multiplication.
00:18 Next, we use the formula for dividing powers.
00:22 When dividing powers with the same base, like A, with exponents.
00:28 Subtract the exponents. That's A to the power of M minus N.
00:33 We will use this formula in our exercise.
00:37 Let's equate the numbers to the unknowns and keep the base.
00:46 Now, subtract the exponents, so let's calculate.
01:01 Great! Now for the power of a power rule.
01:06 Take A raised to M, then raised again to N.
01:11 The result is A to the power of M times N.
01:15 We'll apply this formula in our exercise.
01:19 Again, match the numbers to our formula.
01:23 Keep the base and multiply the exponents.
01:27 And that's how we find the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Reduce the following equation:

(x3)2×y5y3= \frac{\left(x^3\right)^2\times y^5}{y^3}=

2

Step-by-step solution

To solve the problem of reducing the expression (x3)2×y5y3\frac{\left(x^3\right)^2 \times y^5}{y^3}, we'll follow these steps:

  • Step 1: Simplify (x3)2\left(x^3\right)^2 using the power of a power rule.

  • Step 2: Simplify the expression using the division rule for y5y^5 divided by y3y^3.

Let's execute these steps:

Step 1: Apply the power of a power rule to (x3)2\left(x^3\right)^2.

According to the power of a power rule, (xm)n=xmn(x^m)^n = x^{m \cdot n}.

So, (x3)2=x32=x6\left(x^3\right)^2 = x^{3 \cdot 2} = x^6.

Step 2: Simplify the division of exponents for the yy variable.

The expression now looks like x6×y5y3\frac{x^6 \times y^5}{y^3}.

Using the division rule for exponents, ym/yn=ymny^m / y^n = y^{m-n}, we get:

y5/y3=y53=y2y^5 / y^3 = y^{5-3} = y^2.

Final Expression: Combining the results from Step 1 and Step 2, we obtain:

x6×y2x^6 \times y^2.

Therefore, the solution to the problem is x6×y2x^6 \times y^2.

3

Final Answer

x6×y2 x^6\times y^2

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a power to a power, multiply the exponents
  • Technique: (x3)2=x3×2=x6 (x^3)^2 = x^{3 \times 2} = x^6 by multiplying exponents
  • Check: Verify y5y3=y53=y2 \frac{y^5}{y^3} = y^{5-3} = y^2 using subtraction rule ✓

Common Mistakes

Avoid these frequent errors
  • Adding exponents instead of multiplying when raising a power to a power
    Don't calculate (x3)2=x3+2=x5 (x^3)^2 = x^{3+2} = x^5 by adding! This gives the wrong answer. The power rule requires multiplication, not addition. Always multiply the exponents: (x3)2=x3×2=x6 (x^3)^2 = x^{3 \times 2} = x^6 .

Practice Quiz

Test your knowledge with interactive questions

\( \frac{2^4}{2^3}= \)

FAQ

Everything you need to know about this question

When do I multiply exponents and when do I add them?

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Multiply when raising a power to a power: (x3)2=x3×2=x6 (x^3)^2 = x^{3 \times 2} = x^6 . Add when multiplying same bases: x3×x2=x3+2=x5 x^3 \times x^2 = x^{3+2} = x^5 .

Why does y5y3 \frac{y^5}{y^3} become y2 y^2 ?

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When dividing powers with the same base, subtract the exponents: y5y3=y53=y2 \frac{y^5}{y^3} = y^{5-3} = y^2 . This is the quotient rule for exponents.

What if I have negative exponents in my answer?

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Negative exponents are valid! If you get y1 y^{-1} , it equals 1y \frac{1}{y} . Always double-check your subtraction when dividing powers.

Can I simplify the multiplication sign between x6 x^6 and y2 y^2 ?

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Yes! In algebra, x6×y2 x^6 \times y^2 can be written as x6y2 x^6y^2 without the multiplication symbol. Both forms are correct.

How do I check if my final answer is right?

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Substitute simple values like x=1, y=1 into both the original expression and your answer. If they give the same result, you're correct!

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