The rules of exponentiation are rules that help us perform operations like addition, subtraction, multiplication, and division with powers . In certain exercises, if the rules of exponentiation are not used correctly, it will be very difficult to find the solution, so it's important to know them.
Don't worry! These aren't complicated rules. If you make an effort to understand them and practice enough, you'll be able to apply them easily.
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Multiplication of Powers with the Same Base a n ⋅ a m = a n + m a^n\cdot a^m=a^{n+m} a n ⋅ a m = a n + m
If we multiply powers with the same base , the exponent of the result will be equal to the sum of the exponents.
For example 5 2 ⋅ 5 3 = 5 2 + 3 = 5 5 5^2\cdot5^3=5^{2+3}=5^5 5 2 ⋅ 5 3 = 5 2 + 3 = 5 5
7 X + 1 ⋅ 7 2 X + 2 = 7 3 X + 3 7^{X+1}\cdot7^{2X+2}=7^{3X+3} 7 X + 1 ⋅ 7 2 X + 2 = 7 3 X + 3
X 4 ⋅ X 5 = X 4 + 5 = X 9 X^4\cdot X^5=X^{4+5}=X^9 X 4 ⋅ X 5 = X 4 + 5 = X 9
Do you know what the answer is?
Division of Powers with the Same Base a n a m = a n − m \frac{a^n}{a^m}=a^{n-m} a m a n = a n − m
a ≠ 0 a≠0 a = 0
When we divide powers with the same base , the exponent of the result will be equal to the difference of the exponents.
For example
5 4 5 3 = 5 4 − 3 = 5 1 \frac{5^4}{5^3}=5^{4-3}=5^1 5 3 5 4 = 5 4 − 3 = 5 1
7 2 X 7 X = 7 2 X − X = 7 X \frac{7^{2X}}{7^X}=7^{2X-X}=7^X 7 X 7 2 X = 7 2 X − X = 7 X
X 7 X 5 = X 7 − 5 = X 2 \frac{X^7}{X^5}=X^{7-5}=X^2 X 5 X 7 = X 7 − 5 = X 2
Check your understanding
Question 1 a \( 3^{-4}\times2^{-4}\times4^{-4}\times6^{-4} \)
b \( 3\times2\times4\times6 \)
Correct Answer: \( 3^{-4}\times2^{-4}\times4^{-4}\times6^{-4} \)
Question 2 a \( 4^2\times7^2\times3^2 \)
Correct Answer: \( 4^2\times7^2\times3^2 \)
Powers of Powers Let's look at the following example of power of a power
( a n ) m = a n ⋅ m \left(a^n\right)^m=a^{n\cdot m} ( a n ) m = a n ⋅ m
When we come across a power of a power, the result will be the multiplication of those powers.
For example ( a 2 ) 3 = a 2 ⋅ 3 = a 6 \left(a^2\right)^3=a^{2\cdot3}=a^6 ( a 2 ) 3 = a 2 ⋅ 3 = a 6
( a X ) 2 = a 2 X \left(a^X\right)^2=a^{2X} ( a X ) 2 = a 2 X
Do you think you will be able to solve it?
Power of the Multiplication of Several Terms ( a ⋅ b ⋅ c ) n = a n ⋅ b n ⋅ c n \left(a\cdot b\cdot c\right)^n=a^n\cdot b^n\cdot c^n ( a ⋅ b ⋅ c ) n = a n ⋅ b n ⋅ c n
For example ( 2 ⋅ 3 ⋅ 4 ) 2 = 2 2 ⋅ 3 2 ⋅ 4 2 \left(2\cdot3\cdot4\right)^2=2^2\cdot3^2\cdot4^2 ( 2 ⋅ 3 ⋅ 4 ) 2 = 2 2 ⋅ 3 2 ⋅ 4 2
( X ⋅ 2 ⋅ X ) 2 = X 2 ⋅ 2 2 ⋅ X 2 \left(X\cdot2\cdot X\right)^2=X^2\cdot2^2\cdot X^2 ( X ⋅ 2 ⋅ X ) 2 = X 2 ⋅ 2 2 ⋅ X 2
( X 2 ⋅ 2 ⋅ y 3 ) 2 = X 4 ⋅ 2 2 ⋅ y 6 \left(X^2\cdot2\cdot y^3\right)^2=X^4\cdot2^2\cdot y^6 ( X 2 ⋅ 2 ⋅ y 3 ) 2 = X 4 ⋅ 2 2 ⋅ y 6
Test your knowledge
Question 1 a \( a^7\times b\times c\times4 \)
b \( a^7\times b^7\times c^7\times4^7 \)
Correct Answer: \( a^7\times b^7\times c^7\times4^7 \)
Question 2 b \( a^5\cdot30^5\cdot y^5 \)
Correct Answer: \( a^5\cdot30^5\cdot y^5 \)
Fractional Exponents ( a b ) n = a n b n (\frac{a}{b})^n=\frac{a^n}{b^n} ( b a ) n = b n a n
For example ( 5 3 ) 2 = 5 2 3 2 (\frac{5}{3})^2=\frac{5^2}{3^2} ( 3 5 ) 2 = 3 2 5 2
( X y ) 3 = X 3 y 3 (\frac{X}{y})^3=\frac{X^3}{y^3} ( y X ) 3 = y 3 X 3
Do you know what the answer is?
Negative Exponents Let's look at the following example of a negative exponent
a − n = 1 a n a^{-n}=\frac{1}{a^n} a − n = a n 1
1 a − n = a n \frac{1}{a^{-n}}=a^n a − n 1 = a n
This rule is often used to get rid of negative exponents.
For example 5 − 2 = 1 5 2 = 1 25 5^{-2}=\frac{1}{5^2}=\frac{1}{25} 5 − 2 = 5 2 1 = 25 1
1 2 − 3 = 2 3 = 8 \frac{1}{2^{-3}}=2^3=8 2 − 3 1 = 2 3 = 8
Rules for Raising 0 to a Power a 0 = 1 a^0=1 a 0 = 1
Any number raised to the power of 0 0 0 equals 1 1 1 .
0 n = 0 0^n=0 0 n = 0
The number 0 0 0 raised to any power (other than 0 0 0 ) equals 0 0 0 .
0 0 0^0 0 0 = undefined
The value of the number 0 0 0 raised to the power of 0 0 0 is undefined.
Rules About Raising 1 to Any Power 1 n = 1 1^n=1 1 n = 1
The number 1 1 1 raised to any power is equal to 1 1 1 .
Do you think you will be able to solve it?
Question 1 a \( 3^{-4}\times2^{-4}\times4^{-4}\times6^{-4} \)
b \( 3\times2\times4\times6 \)
Correct Answer: \( 3^{-4}\times2^{-4}\times4^{-4}\times6^{-4} \)
Question 2 b \( 4^2\times7^2\times3^2 \)
Correct Answer: \( 4^2\times7^2\times3^2 \)
Power Exercises Exercise 1: ( Variables in the value of the power) Task:
Solve the following equation:
( A m ) n (A^m)^n ( A m ) n
( 4 X ) 2 (4^X)^2 ( 4 X ) 2
Solution:
( 4 X ) 2 = 4 X × 2 (4^X)^2=4^{X\times2} ( 4 X ) 2 = 4 X × 2
Exercise 2: (Number of Elements) ( a m ) n = a m × n (a^m)n^=a^{m\times n} ( a m ) n = a m × n
Task:
Solve the exercise:
( X 2 × 3 ) 2 = ? (X²\times3)²=\text{?} ( X 2 × 3 ) 2 = ?
Solution:
( X 2 × 3 ) 2 = X 2 × 2 × 3 2 = X 4 × 9 = 9 X 4 (X²\times3)²=X^{2\times2}\times3²=X^4\times9=9X^4 ( X 2 × 3 ) 2 = X 2 × 2 × 3 2 = X 4 × 9 = 9 X 4
Before the formula:
( a × b ) m = a m × b m (a\times b)^{m=}a^m\times b^m ( a × b ) m = a m × b m
And also
( a m ) n = (a^m)^n= ( a m ) n = Power of a power
Answer:
9 X 4 9X^4 9 X 4
Exercise 3 Task:
Solve the exercise:
( ( 7 ⋅ 3 ) 2 ) 6 + ( 3 − 1 ) 3 ⋅ ( 2 3 ) 4 = ? ((7\cdot3)^2)^6+(3^{-1})^3\cdot(2^3)^4=\text{?} (( 7 ⋅ 3 ) 2 ) 6 + ( 3 − 1 ) 3 ⋅ ( 2 3 ) 4 = ?
Solution:
( 7 ⋅ 3 ) 2 ⋅ 6 + 3 − 1 ⋅ 3 ⋅ 2 3 ⋅ 4 = ? (7\cdot3)^{2\cdot6}+3^{-1\cdot3}\cdot2^{3\cdot4}=\text{?} ( 7 ⋅ 3 ) 2 ⋅ 6 + 3 − 1 ⋅ 3 ⋅ 2 3 ⋅ 4 = ?
2 1 12 + 3 − 3 ⋅ 2 12 = ? 21^{12}+3^{-3}\cdot2^{12}=\text{?} 2 1 12 + 3 − 3 ⋅ 2 12 = ?
Answer:
2 1 12 + 3 − 3 ⋅ 2 12 21^{12}+3^{-3}\cdot2^{12} 2 1 12 + 3 − 3 ⋅ 2 12
For problems like the following, you can use the formula:
( a m ) n = a m ⋅ n (a^m)^n=a^{m\cdot n} ( a m ) n = a m ⋅ n
Exercise 4: (Properties of Powers) Task:
Solve the following equation:
2 3 ⋅ 2 4 + ( 4 3 ) 2 + 2 5 2 3 = 2^3\cdot2^4+(4^3)^2+\frac{2^5}{2^3}= 2 3 ⋅ 2 4 + ( 4 3 ) 2 + 2 3 2 5 =
Solution:
2 3 ⋅ 2 4 + ( 4 3 ) 2 + 2 5 2 3 = 2^3\cdot2^4+(4^3)^2+\frac{2^5}{2^3}= 2 3 ⋅ 2 4 + ( 4 3 ) 2 + 2 3 2 5 =
2 3 + 4 + 4 3 ⋅ 2 + 2 ( 5 − 3 ) = 2 7 + 4 6 + 2 2 2^{3+4}+4^{3\cdot2}+2^{(5-3)}=2^7+4^6+2^2 2 3 + 4 + 4 3 ⋅ 2 + 2 ( 5 − 3 ) = 2 7 + 4 6 + 2 2
Answer:
2 7 + 4 6 + 2 2 2^7+4^6+2^2 2 7 + 4 6 + 2 2
The answer is supported by a series of properties:
( a m ) n = a m ⋅ n (a^m)^n=a^{m\cdot n} ( a m ) n = a m ⋅ n a X a Y = a X − Y \frac{a^X}{a^Y}=a^{X-Y} a Y a X = a X − Y a X ⋅ a Y = a X + Y a^X\cdot a^Y=a^{X+Y} a X ⋅ a Y = a X + Y
Do you know what the answer is?
Question 1 a \( a^7\times b^7\times c^7\times4^7 \)
b \( a^7\times b\times c\times4 \)
Correct Answer: \( a^7\times b^7\times c^7\times4^7 \)
Question 2 b \( a^5\cdot30^5\cdot y^5 \)
Correct Answer: \( a^5\cdot30^5\cdot y^5 \)
Exercise 5 Task:
Which expression has the greatest value?
1 0 2 , 2 4 , 3 7 , 5 5 10^{2},2^{4},3^{7},5^{5} 1 0 2 , 2 4 , 3 7 , 5 5
Solution:
1 0 2 = 100 10^2=100 1 0 2 = 100
2 4 = 16 2^4=16 2 4 = 16
3 7 = 2187 3^7=2187 3 7 = 2187
5 5 = 3125 5^5=3125 5 5 = 3125
Answer:
The greatest value is 5 5 5^5 5 5
Exercise 6 Task:
Solve the following equation:
( ( 4 X ) 3 Y ) 2 ((4X)^{3Y})^2 (( 4 X ) 3 Y ) 2
Solution:
( 4 X ) 3 Y ⋅ 2 = 4 X 6 Y (4X)^{3Y\cdot2}=4X^{6Y} ( 4 X ) 3 Y ⋅ 2 = 4 X 6 Y
Exercise 7 Formula:
( a m ) n = a m ⋅ n (a^m)^n=a^{m\cdot n} ( a m ) n = a m ⋅ n
Assignment:
Solve the following equation:
( 4 2 ) 3 + ( 9 3 ) 4 = ? (4^2)^3+(9^3)^4=\text{?} ( 4 2 ) 3 + ( 9 3 ) 4 = ?
Solution:
( 4 2 ) 3 + ( 9 3 ) 4 = ? (4^2)^3+(9^3)^4=\text{?} ( 4 2 ) 3 + ( 9 3 ) 4 = ?
4 2 ⋅ 3 + 9 3 ⋅ 4 = 4 6 + 9 12 4^{2\cdot3}+9^{3\cdot4}=4^6+9^{12} 4 2 ⋅ 3 + 9 3 ⋅ 4 = 4 6 + 9 12
Answer:
4 6 + 9 12 4^6+9^{12} 4 6 + 9 12
Questions and Answers on the Topic of Exponentiation What are the laws of exponents?
Multiplication with the same bases, division with the same bases, and power of powers.
How is multiplication with the same bases done?
The exponents are added.
How is division with the same bases done?
The exponents are subtracted.
What is a number raised to the 0 equal to?
One, as long as the base is not zero.
Do you think you will be able to solve it?
Examples with solutions for Exponents Rules Exercise #1 11 2 0 = ? 112^0=\text{?} 11 2 0 = ?
Video Solution Step-by-Step Solution We use the zero exponent rule.
X 0 = 1 X^0=1 X 0 = 1 We obtain
11 2 0 = 1 112^0=1 11 2 0 = 1 Therefore, the correct answer is option C.
Answer Exercise #2 2 4 2 3 = \frac{2^4}{2^3}= 2 3 2 4 =
Video Solution Step-by-Step Solution Let's keep in mind that the numerator and denominator of the fraction have terms with the same base, therefore we use the property of powers to divide between terms with the same base:
b m b n = b m − n \frac{b^m}{b^n}=b^{m-n} b n b m = b m − n We apply it in the problem:
2 4 2 3 = 2 4 − 3 = 2 1 \frac{2^4}{2^3}=2^{4-3}=2^1 2 3 2 4 = 2 4 − 3 = 2 1 Remember that any number raised to the 1st power is equal to the number itself, meaning that:
b 1 = b b^1=b b 1 = b Therefore, in the problem we obtain:
2 1 = 2 2^1=2 2 1 = 2 Therefore, the correct answer is option a.
Answer Exercise #3 Video Solution Step-by-Step Solution To solve the exercise we use the power property:( a n ) m = a n ⋅ m (a^n)^m=a^{n\cdot m} ( a n ) m = a n ⋅ m
We use the property with our exercise and solve:
( 3 5 ) 4 = 3 5 × 4 = 3 20 (3^5)^4=3^{5\times4}=3^{20} ( 3 5 ) 4 = 3 5 × 4 = 3 20
Answer Exercise #4 Video Solution Step-by-Step Solution We use the power property:
X 0 = 1 X^0=1 X 0 = 1 We apply it to the problem:
5 0 = 1 5^0=1 5 0 = 1 Therefore, the correct answer is C.
Answer Exercise #5 ( 6 2 ) 13 = (6^2)^{13}= ( 6 2 ) 13 =
Video Solution Step-by-Step Solution We use the formula:
( a n ) m = a n × m (a^n)^m=a^{n\times m} ( a n ) m = a n × m
Therefore, we obtain:
6 2 × 13 = 6 26 6^{2\times13}=6^{26} 6 2 × 13 = 6 26
Answer