Simplify and Expand: The Expression (x+y+1)²

Trinomial Expansion with Three-Term Squares

Simplify the expression (x+y+1)2 (x+y+1)^2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:05 Let's simplify this expression step by step.
00:11 First, we'll use the multiplication formulas to open the parentheses.
00:18 Here, think of X plus Y as A.
00:24 And one as B.
00:31 Let's substitute these into our formula now.
00:40 Again, use multiplication formulas to expand the parentheses.
00:44 This time, X is A.
00:48 And Y is B.
00:52 Let's carefully substitute them into the formula now.
01:04 Multiply each term inside the parentheses correctly.
01:21 Now let's arrange the equation neatly.
01:30 And there you have it, the solution to the problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify the expression (x+y+1)2 (x+y+1)^2

2

Step-by-step solution

To solve this problem, we'll simplify the expression (x+y+1)2(x+y+1)^2 by recognizing it as a square of a sum involving three terms:

  • Step 1: Use the formula (a+b+c)2=a2+b2+c2+2ab+2ac+2bc(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc.
  • Step 2: Identify a=xa = x, b=yb = y, and c=1c = 1.
  • Step 3: Substitute these values into the formula.
  • Step 4: Calculate each square and product term.
  • Step 5: Simplify the expression by combining all computed terms.

Now, let's work through the steps:

We start with the formula: (x+y+1)2=x2+y2+12+2xy+2x1+2y1(x+y+1)^2 = x^2 + y^2 + 1^2 + 2xy + 2 \cdot x \cdot 1 + 2 \cdot y \cdot 1

Calculate each component:

  • x2x^2 remains x2x^2.
  • y2y^2 remains y2y^2.
  • 121^2 results in 11.
  • The term 2xy2xy results from the cross-product of xx and yy.
  • The term 2x12 \cdot x \cdot 1 simplifies to 2x2x.
  • The term 2y12 \cdot y \cdot 1 simplifies to 2y2y.

Combine these elements to form the simplified expression:

x2+y2+1+2xy+2x+2y x^2 + y^2 + 1 + 2xy + 2x + 2y

Thus, the simplified expression for (x+y+1)2(x+y+1)^2 is:

x2+2x+y2+2y+2xy+1x^2 + 2x + y^2 + 2y + 2xy + 1.

This corresponds to choice number 4 in the provided options.

3

Final Answer

x2+2x+y2+2y+2xy+1 x^2+2x+y^2+2y+2xy+1

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use (a+b+c)² = a² + b² + c² + 2ab + 2ac + 2bc
  • Technique: Calculate squares first: x², y², 1² = 1, then cross products
  • Check: Count 6 terms total: x² + 2x + y² + 2y + 2xy + 1 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting cross-product terms when expanding
    Don't expand (x+y+1)² as just x² + y² + 1 = missing 3 terms! This ignores the essential cross-products between all pairs. Always include all 6 terms: 3 squares plus 3 cross-products (2ab + 2ac + 2bc).

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that has the same value as the following:


\( (x+3)^2 \)

FAQ

Everything you need to know about this question

Why are there 6 terms instead of 3?

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When you square a trinomial, you get 3 squared terms (x², y², 1²) plus 3 cross-products (2xy, 2x, 2y). Each pair of different terms creates a cross-product!

How do I remember the trinomial square formula?

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Think "square each term, then double every pair"! For (a+b+c)2 (a+b+c)^2 , you get: a² + b² + c² + 2ab + 2ac + 2bc.

Can I use FOIL for three terms?

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No! FOIL only works for two terms. For trinomials like (x+y+1)², you need the full trinomial square formula or multiply (x+y+1)(x+y+1) term by term.

Why is the coefficient 2 in front of cross-products?

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Because each pair appears twice when you expand! For example, xy appears once from x·y and once from y·x, so you get 2xy total.

What if one term is negative like (x+y-1)²?

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The formula still works! Just be careful with signs. (x+y1)2 (x+y-1)^2 gives you x² + y² + 1 + 2xy - 2x - 2y because (-1) makes some cross-products negative.

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