Simplify the Rational Expression: (10x²-2x)/(5x-1)

Rational Expressions with Common Factor Reduction

Simplify the following expression:

10x22x5x1 \frac{10x^2-2x}{5x-1}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:03 Let's break down 10 into factors 5 and 2
00:06 Let's break down the power into multiplications
00:15 Let's mark the common factors
00:36 Let's take out the common factors from the parentheses
00:47 Let's reduce what we can
00:54 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify the following expression:

10x22x5x1 \frac{10x^2-2x}{5x-1}

2

Step-by-step solution

Let's simplify the given expression:

10x22x5x1 \frac{10x^2-2x}{5x-1} Remember that we can reduce complete expressions only when both the numerator and denominator are completely factored into multiplication expressions,

We must first use factorization, identify that in the numerator we can factor out a common term, then reduce the expressions in the resulting fraction:

10x22x5x12x(5x1)5x12x \frac{10x^2-2x}{5x-1} \\ \frac{2x(5x-1)}{5x-1} \\ \downarrow\\ \boxed{2x} Therefore, the correct answer is answer A.

3

Final Answer

2x 2x

Key Points to Remember

Essential concepts to master this topic
  • Factorization Rule: Factor numerator completely before attempting to cancel terms
  • Technique: Factor out 2x from 10x²-2x to get 2x(5x-1)
  • Check: Multiply 2x by (5x-1) to verify: 2x(5x-1) = 10x²-2x ✓

Common Mistakes

Avoid these frequent errors
  • Canceling terms without complete factorization
    Don't try to cancel x from 10x² and 5x directly = wrong answer like 2x-2! This ignores proper algebraic rules. Always factor the numerator completely first, then cancel only common factors that appear in both numerator and denominator.

Practice Quiz

Test your knowledge with interactive questions

Identify the field of application of the following fraction:

\( \frac{7}{13+x} \)

FAQ

Everything you need to know about this question

Why can't I just cancel the x terms directly?

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You can only cancel complete factors, not individual terms! The expression 10x22x 10x^2-2x has terms connected by subtraction, so you must factor first to reveal the common factor.

How do I know when I can cancel something?

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You can cancel when the same factor appears in both the numerator and denominator. After factoring, we got 2x(5x1)5x1 \frac{2x(5x-1)}{5x-1} , and (5x-1) appears in both places.

What if the denominator doesn't factor out completely?

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That's fine! You can only cancel the parts that do factor out. Sometimes expressions don't simplify completely, and that's the final answer.

Do I need to worry about when x makes the denominator zero?

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Yes! The original expression is undefined when 5x1=0 5x-1 = 0 , so x15 x \neq \frac{1}{5} . Even after simplifying to 2x, this restriction still applies.

How can I check if my factoring is correct?

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Multiply out your factored form! If 2x(5x1) 2x(5x-1) gives you back 10x22x 10x^2-2x , then your factoring is correct.

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