Simplify the Rational Expression: (5x²-1)/(15x⁴-3x²)

Rational Expressions with Common Factor Reduction

Simplify:

5x2115x43x2 \frac{5x^2-1}{15x^4-3x^2}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:04 Let's factorize 15 into factors 5 and 3
00:10 Let's break down power of 4 into 2 squared factors
00:20 Let's mark the common factors
00:41 Let's take out the common factors from the parentheses
00:53 Let's reduce what we can
01:00 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify:

5x2115x43x2 \frac{5x^2-1}{15x^4-3x^2}

2

Step-by-step solution

Let's simplify the given expression:

5x2115x43x2 \frac{5x^2-1}{15x^4-3x^2} Remember that we can reduce complete expressions only when both the numerator and denominator are completely factored into multiplication expressions,

For this, we'll use factorization, identify that in the denominator we can factor out a common term, do this, then reduce the expressions possible in the fraction we got (reduction sign):

5x2115x43x25x213x2(5x21)13x2 \frac{5x^2-1}{15x^4-3x^2} \\ \frac{5x^2-1}{3x^2(5x^2-1)} \\ \downarrow\\ \boxed{\frac{1}{3x^2}} In the first stage, to factor out the common term in the denominator, we also used the law of exponents:aman=am+n a^m\cdot a^n=a^{m+n}

Therefore, the correct answer is answer B.

3

Final Answer

13x2 \frac{1}{3x^2}

Key Points to Remember

Essential concepts to master this topic
  • Factoring Rule: Both numerator and denominator must be completely factored first
  • Technique: Factor out 3x2 3x^2 from denominator: 15x43x2=3x2(5x21) 15x^4-3x^2 = 3x^2(5x^2-1)
  • Check: Multiply simplified result by denominator should give original numerator ✓

Common Mistakes

Avoid these frequent errors
  • Trying to cancel terms instead of factors
    Don't cancel individual terms like the 5x² in numerator with 15x⁴ in denominator = incorrect simplification! Terms can only be reduced when they are complete factors of both numerator and denominator. Always factor completely first, then cancel identical factors.

Practice Quiz

Test your knowledge with interactive questions

Determine if the simplification shown below is correct:

\( \frac{7}{7\cdot8}=8 \)

FAQ

Everything you need to know about this question

Why can't I just divide the coefficients and subtract the exponents?

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You can only do this when expressions are multiplied together, not when they're added or subtracted! Since we have 5x21 5x^2-1 (subtraction), we must factor first before simplifying.

How do I know what to factor out from the denominator?

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Look for the greatest common factor (GCF) of all terms. Here, both 15x4 15x^4 and 3x2 3x^2 are divisible by 3x2 3x^2 , so factor that out first.

What if the numerator doesn't factor nicely?

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That's okay! In this problem, 5x21 5x^2-1 doesn't factor further with real numbers. The key is factoring the denominator to reveal the common factor (5x21) (5x^2-1) that cancels.

Can I cancel the x² terms directly?

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No! You can only cancel complete factors, not individual terms within a sum or difference. Always factor first, then look for identical factors in numerator and denominator to cancel.

How do I check if my simplified answer is correct?

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Multiply your answer by the original denominator. You should get the original numerator: 13x2×(15x43x2)=5x21 \frac{1}{3x^2} \times (15x^4-3x^2) = 5x^2-1

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