Solve the following exercise:12+3⋅0= 12+3\cdot0= 12+3⋅0=
According to the order of operations, we first multiply and then add:
12+(3⋅0)= 12+(3\cdot0)= 12+(3⋅0)=
3×0=0 3\times0=0 3×0=0
12+0=12 12+0=12 12+0=12
12 12 12