Solve (√16 - 2² + 6) ÷ 2²: Order of Operations Challenge

(1622+6):22= (\sqrt{16}-2^2+6):2^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 Break down 16 to 4 squared
00:12 The square root of any squared number cancels the square
00:18 Let's use this formula in our exercise
00:28 Calculate the powers
00:40 Always calculate the parentheses first, according to the proper order of operations
00:49 This is the solution

Step-by-step written solution

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1

Understand the problem

(1622+6):22= (\sqrt{16}-2^2+6):2^2=

2

Step-by-step solution

Let's solve the expression given in the problem: (1622+6):22= (\sqrt{16}-2^2+6):2^2=

We need to follow the Order of Operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction). This ensures that we perform calculations in the correct order:

  • 16 \sqrt{16} simplifies to 4 4 because the square root of 16 is 4.
  • Next, evaluate 22 2^2 , which equals 4 4 .
  • Replace these results back into the expression: (44+6):4 (4-4+6):4 .

Now let's go step-by-step through the simplified expression:

  • Calculate inside the parentheses: 44+6 4 - 4 + 6 .
  • 44 4-4 equals 0 0 .
  • Then, 0+6 0+6 equals 6 6 .
  • We now have 6:4 6:4 , which denotes division.
  • Perform the division: 6÷4=1.5 6 \div 4 = 1.5 .

Thus, the solution to the expression is: 1.5 1.5 .

3

Final Answer

1.5

Practice Quiz

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What is the result of the following equation?

\( 36-4\div2 \)

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