Solve (√16 - 2² + 6) ÷ 2²: Order of Operations Challenge

Question

(1622+6):22= (\sqrt{16}-2^2+6):2^2=

Video Solution

Solution Steps

00:00 Solve
00:03 Let's break down 16 to 4 squared
00:12 The square root of any squared number cancels the square
00:18 Let's use this formula in our exercise
00:28 Let's calculate the powers
00:40 Always calculate parentheses first, according to proper order of operations inside
00:49 And this is the solution to the question

Step-by-Step Solution

Let's solve the expression given in the problem: (1622+6):22= (\sqrt{16}-2^2+6):2^2=

We need to follow the Order of Operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction). This ensures that we perform calculations in the correct order:

  • 16 \sqrt{16} simplifies to 4 4 because the square root of 16 is 4.
  • Next, evaluate 22 2^2 , which equals 4 4 .
  • Replace these results back into the expression: (44+6):4 (4-4+6):4 .

Now let's go step-by-step through the simplified expression:

  • Calculate inside the parentheses: 44+6 4 - 4 + 6 .
  • 44 4-4 equals 0 0 .
  • Then, 0+6 0+6 equals 6 6 .
  • We now have 6:4 6:4 , which denotes division.
  • Perform the division: 6÷4=1.5 6 \div 4 = 1.5 .

Thus, the solution to the expression is: 1.5 1.5 .

Answer

1.5