Evaluate (4² + 3) × √9: Order of Operations Practice

(42+3)×9= (4^2+3)\times\sqrt{9}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:06 Let's solve this problem together!
00:09 First, calculate 4 squared. That means 4 times 4.
00:17 Remember, always do the parentheses first.
00:24 Let's break down 9 into 3 squared. So, 3 times 3.
00:30 Square root cancels out a square number.
00:35 We'll apply this formula in our exercise.
00:44 And that's how we solve this problem!

Step-by-step written solution

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1

Understand the problem

(42+3)×9= (4^2+3)\times\sqrt{9}=

2

Step-by-step solution

To solve the expression (42+3)×9=(4^2+3)\times\sqrt{9}= , we need to follow the order of operations, also known as PEMDAS/BODMAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).


  • First, we deal with the exponent 424^2, which means 4 raised to the power of 2. Calculate 42=164^2 = 16.

  • Next, we calculate the expression inside the parentheses: (42+3)(4^2+3). We already know 42=164^2 = 16, so we add 3 to 16: 16+3=1916 + 3 = 19.

  • Then, we find the square root of 9: 9=3\sqrt{9} = 3.

  • Lastly, we perform the multiplication: 19×3=5719 \times 3 = 57.

Thus, the final result of the expression (42+3)×9(4^2+3)\times\sqrt{9} is 57.

3

Final Answer

57

Practice Quiz

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What is the result of the following equation?

\( 36-4\div2 \)

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