Evaluate (4² + 3) × √9: Order of Operations Practice

Question

(42+3)×9= (4^2+3)\times\sqrt{9}=

Video Solution

Solution Steps

00:00 Solve
00:03 Calculate 4 squared
00:11 Always calculate parentheses first
00:18 Break down 9 to 3 squared
00:24 The square root of any squared number cancels out the root
00:29 We'll use this formula in our exercise
00:38 And this is the solution to the question

Step-by-Step Solution

To solve the expression (42+3)×9=(4^2+3)\times\sqrt{9}= , we need to follow the order of operations, also known as PEMDAS/BODMAS (Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right)).


  • First, we deal with the exponent 424^2, which means 4 raised to the power of 2. Calculate 42=164^2 = 16.

  • Next, we calculate the expression inside the parentheses: (42+3)(4^2+3). We already know 42=164^2 = 16, so we add 3 to 16: 16+3=1916 + 3 = 19.

  • Then, we find the square root of 9: 9=3\sqrt{9} = 3.

  • Lastly, we perform the multiplication: 19×3=5719 \times 3 = 57.

Thus, the final result of the expression (42+3)×9(4^2+3)\times\sqrt{9} is 57.

Answer

57