Solve ((4×6)³)⁴: Calculating Nested Exponents Step-by-Step

Power Rule with Nested Exponents

Insert the corresponding expression:

((4×6)3)4= \left(\right.\left(4\times6\right)^3)^4=

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1

Understand the problem

Insert the corresponding expression:

((4×6)3)4= \left(\right.\left(4\times6\right)^3)^4=

2

Step-by-step solution

To solve this problem, we'll use the power of a power property of exponents, which states that for any base aa and exponents mm and nn, (am)n=am×n(a^m)^n = a^{m \times n}.

  • Step 1: Identify the base and exponents:
    In the given expression ((4×6)3)4 \left(\left(4 \times 6\right)^3\right)^4, the base is (4×6)(4 \times 6), the inner exponent is 3, and the outer exponent is 4.

  • Step 2: Apply the power of a power rule:
    According to the rule, ((4×6)3)4\left((4 \times 6)^3\right)^4 simplifies to (4×6)3×4(4 \times 6)^{3 \times 4}.

  • Step 3: Calculate the new exponent:
    Multiply the exponents: 3×4=123 \times 4 = 12. Hence, the expression simplifies to (4×6)12 (4 \times 6)^{12} .

The expression ((4×6)3)4 \left(\left(4 \times 6\right)^3\right)^4 is equivalent to (4×6)3×4(4 \times 6)^{3 \times 4}. Therefore, the correct choice is:

(4×6)3×4 \left(4\times6\right)^{3\times4}

Therefore, the correct answer is Choice 1.

3

Final Answer

(4×6)3×4 \left(4\times6\right)^{3\times4}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a power to another power, multiply exponents
  • Technique: (am)n=am×n (a^m)^n = a^{m \times n} gives (4×6)3×4 (4 \times 6)^{3 \times 4}
  • Check: Verify by calculating: 3 × 4 = 12 makes (24)12 (24)^{12}

Common Mistakes

Avoid these frequent errors
  • Adding exponents instead of multiplying
    Don't add 3 + 4 = 7 to get (4×6)7 (4 \times 6)^7 = wrong answer! Adding only works when multiplying same bases, not raising powers to powers. Always multiply exponents when you see (am)n (a^m)^n .

Practice Quiz

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\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why do I multiply 3 × 4 instead of adding them?

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The power rule says (am)n=am×n (a^m)^n = a^{m \times n} . You're taking something that's already raised to the 3rd power and raising it to the 4th power again. That means multiplying the base by itself 3 × 4 = 12 times total!

What's the difference between this and a3×a4 a^3 \times a^4 ?

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Great question! a3×a4=a3+4=a7 a^3 \times a^4 = a^{3+4} = a^7 (you add when multiplying same bases). But (a3)4=a3×4=a12 (a^3)^4 = a^{3 \times 4} = a^{12} (you multiply when raising a power to another power).

Do I need to calculate 4 × 6 first?

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Not for this problem! The question asks for the equivalent expression, so keep (4×6) (4 \times 6) as the base and just apply the power rule to get (4×6)12 (4 \times 6)^{12} .

How can I remember when to add vs multiply exponents?

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Memory trick: Multiplication → Addition (a3×a4=a3+4 a^3 \times a^4 = a^{3+4} ) and Power → Multiplication ((a3)4=a3×4 (a^3)^4 = a^{3 \times 4} ). Look for parentheses around the first power!

What if there are three nested exponents like ((a2)3)4 ((a^2)^3)^4 ?

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Work from inside out! First: (a2)3=a2×3=a6 (a^2)^3 = a^{2 \times 3} = a^6 . Then: (a6)4=a6×4=a24 (a^6)^4 = a^{6 \times 4} = a^{24} . Or multiply all at once: a2×3×4=a24 a^{2 \times 3 \times 4} = a^{24} !

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