Solve: 5421 minus 3675 in Vertical Subtraction Format

Video Solution

Solution Steps

00:00 Solve

00:03 Each time we consider borrowing 2 digits, and then we'll place

00:06 1 is less than 5

00:10 Therefore we'll subtract 1 from the tens and add this amount to the ones

00:14 So now instead of 1 we'll have 11

00:17 We'll subtract the ones from the ones plus the ten

00:22 We'll place in the ones

00:26 1 is less than 7

00:31 Therefore we'll subtract 1 from the hundreds and add this amount to the tens

00:37 So now instead of 1 we'll have 11

00:40 We'll subtract the tens from the tens plus the ten

00:46 We'll place in the tens

00:52 3 is less than 6

00:58 Therefore we'll subtract 1 from the thousands and add this amount to the hundreds

01:03 So now instead of 3 we'll have 13

01:07 We'll subtract the hundreds from the hundreds plus the hundred

01:12 We'll place in the hundreds

01:17 We'll subtract thousands from thousands, and place in thousands

01:20 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll execute vertical subtraction with regrouping as follows:

Let's start by aligning the numbers one above the other:
$\begin{array}{c} && 5 & 4 & 2 & 1 \\ - & & 3 & 6 & 7 & 5 \\ \hline \end{array}$

We begin subtraction from the rightmost digits (units place):

Units: $1 - 5$ requires borrowing because 1 is less than 5. Borrow 1 from the tens (making it 3), turning 1 into 11. Now, $11 - 5 = 6$ .

Next, subtract the tens:

Tens: $2 - 7$ requires borrowing because 2 is less than 7. Borrow 1 from the hundreds (making it 3), turning 2 into 12. Now, $12 - 7 = 5$ .

Then, subtract the hundreds:

Hundreds: $3 - 6$ requires borrowing because 3 is less than 6. Borrow 1 from the thousands (making it 4), turning 3 into 13. Now, $13 - 6 = 7$ .

Finally, subtract the thousands:

Putting it all together, the result is:

$\begin{array}{c} & 5 & 4 & 2 & 1 \\ - & 3 & 6 & 7 & 5 \\ \hline & 1 & 7 & 4 & 6 \\ \end{array}$

Therefore, the solution to the problem is $1746$ .