Solve Vertical Subtraction: 6210 minus 4242

Let's solve the subtraction problem step-by-step:

We have:

$\begin{array}{c} 6210 \\ - \, 4242 ~~~~\\ \hline \end{array}$

• Step 1: Subtract the units place.

The units digit of the minuend (0) is less than the units digit of the subtrahend (2). We need to borrow. Borrowing from the tens place changes the 1 to a 0 in the tens place and the units place becomes 10. Finally, 10 - 2 = 8.

• Step 2: Subtract the tens place.

After borrowing, the tens digit in the minuend is 0, with the subtrahend having a tens digit of 4. We need to borrow from the hundreds place. Borrowing changes the hundreds digit of the minuend from 2 to 1, and the tens digit becomes 10. Finally, 10 - 4 = 6.

• Step 3: Subtract the hundreds place.

The hundreds digit of the minuend after borrowing is 1, while the subtrahend has 2. We borrow once more from the thousands place. The thousands digit decreases from 6 to 5, making the hundreds digit 11. So, 11 - 2 = 9.

• Step 4: Subtract the thousands place.

Now, the thousands digit of the minuend is 5, and the subtrahend digit is 4. Simply perform the subtraction: 5 - 4 = 1.

Putting it all together, the result of the subtraction is 1968.

Therefore, the solution to the problem is $1968$.