Solve (5/9)^(2x+1): Complete the Exponential Expression

Exponential Expressions with Fractional Bases

Insert the corresponding expression:

(59)2x+1= \left(\frac{5}{9}\right)^{2x+1}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to the power (N)
00:07 equals the numerator and denominator raised to the same power (N)
00:11 Note that each exponent (N) contains an addition operation
00:14 We will apply this formula to our exercise
00:17 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(59)2x+1= \left(\frac{5}{9}\right)^{2x+1}=

2

Step-by-step solution

To solve this problem, we'll apply the power of a fraction rule, which states that (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}.

Step 1: Recognize the given expression: (59)2x+1\left(\frac{5}{9}\right)^{2x+1}.

Step 2: Apply the exponent rule to rewrite the expression. According to the rule, this becomes:

(59)2x+1=52x+192x+1\left(\frac{5}{9}\right)^{2x+1} = \frac{5^{2x+1}}{9^{2x+1}}.

Therefore, the expression can be rewritten as 52x+192x+1\frac{5^{2x+1}}{9^{2x+1}}.

Among the given choices, the correct option is choice 1: 52x+192x+1\frac{5^{2x+1}}{9^{2x+1}}.

Thus, the solution to the problem is 52x+192x+1 \frac{5^{2x+1}}{9^{2x+1}} .

3

Final Answer

52x+192x+1 \frac{5^{2x+1}}{9^{2x+1}}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Apply exponent to both numerator and denominator separately
  • Technique: Transform (59)2x+1 \left(\frac{5}{9}\right)^{2x+1} to 52x+192x+1 \frac{5^{2x+1}}{9^{2x+1}}
  • Check: Verify both parts have identical exponents: 2x+1 appears twice ✓

Common Mistakes

Avoid these frequent errors
  • Adding exponents to numerator and denominator
    Don't write 52x92x+59 \frac{5^{2x}}{9^{2x}}+\frac{5}{9} by treating addition like distribution = completely wrong structure! This confuses addition with exponentiation rules. Always apply the same exponent to both numerator and denominator: (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply the fraction by the exponent?

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Exponents don't work like multiplication! When you raise a fraction to a power, you must raise both parts separately. Think of (59)3 \left(\frac{5}{9}\right)^3 as 59×59×59=5393 \frac{5}{9} \times \frac{5}{9} \times \frac{5}{9} = \frac{5^3}{9^3} .

What if the exponent is just a number like 3?

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The same rule applies! (59)3=5393=125729 \left(\frac{5}{9}\right)^3 = \frac{5^3}{9^3} = \frac{125}{729} . Whether the exponent is a number or an expression like 2x+1, both parts get the same exponent.

How do I know which answer choice is correct?

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Look for the choice where both the numerator and denominator have exactly the same exponent. In this case, both should have 2x+1 2x+1 as the exponent.

Can I simplify the exponent 2x+1 first?

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No need to! The exponent 2x+1 2x+1 should stay exactly as it is. The power rule works with any exponent, whether it's simple or complex.

What's wrong with the other answer choices?

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  • Choice 2 incorrectly adds terms instead of applying exponents
  • Choice 3 only applies the exponent to the numerator
  • Choice 4 only applies the exponent to the denominator

Only choice 1 correctly applies the exponent to both parts!

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