Solve for x in (3/10)^x: Complete the Exponential Expression

Question

Insert the corresponding expression:

(32×5)x= \left(\frac{3}{2\times5}\right)^x=

Video Solution

Solution Steps

00:10 Let's simplify this problem together.
00:14 Remember, if you have a fraction with a power N, both the top and bottom get the same power N.
00:20 So each part of the fraction will be raised to the power of N.
00:25 Now let's try this out with our example.
00:28 When you have a product with a power N, it means each factor gets that power.
00:34 Let’s apply this law to see what happens.
00:38 We'll use this rule in our calculation now.
00:43 And that gives us our solution.

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given expression.
  • Step 2: Apply the exponent rule (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute xx to numerator and denominator.
  • Step 3: Simplify the denominator expression by distributing exponent xx to each factor.

Now, let's work through each step:
Step 1: We have the original expression (32×5)x\left(\frac{3}{2 \times 5}\right)^x.
Step 2: Apply the rule to get 3x(2×5)x\frac{3^x}{(2 \times 5)^x}.
Step 3: Expand the denominator: (2×5)x=2x×5x(2 \times 5)^x = 2^x \times 5^x. This leads us to 3x2x×5x\frac{3^x}{2^x \times 5^x}.

Therefore, the solution to the problem is 3x2x×5x \frac{3^x}{2^x \times 5^x} .

Answer

3x2x×5x \frac{3^x}{2^x\times5^x}