Solve 8a-b(7+a): Evaluating with a=2 and b=1/3

Order of Operations with Fractional Coefficients

Solve the following expression:

8ab(7+a) 8a-b(7+a)

If

a=2,b=13 a=2,b=\frac{1}{3}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Set up and solve
00:03 Substitute appropriate values according to the given data and solve
00:16 Always solve parentheses first
00:20 Continue solving according to proper order of operations
00:26 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following expression:

8ab(7+a) 8a-b(7+a)

If

a=2,b=13 a=2,b=\frac{1}{3}

2

Step-by-step solution

Note that we have two unknowns, a and b, and we are also given values for them,

Therefore, let's start by substituting these values in the equation instead of the unknowns:

8*2-1/3*(7+2)=

When there is a number before parentheses, it's like having a multiplication sign between them.

Let's start solving according to the order of operations, beginning with the parentheses:

8*2-1/3*(9)=

Now let's continue with multiplication and division:

16-9/3=
16-3=

‎‎‎‎‎‎‎13

And that's the solution!

3

Final Answer

13 13

Key Points to Remember

Essential concepts to master this topic
  • Substitution: Replace variables with given values before calculating
  • Order of Operations: Solve parentheses first: (7+2) = 9, then multiply
  • Verification: Check final calculation: 16 - 3 = 13 ✓

Common Mistakes

Avoid these frequent errors
  • Ignoring order of operations with fractions
    Don't solve 8×2 - 13 \frac{1}{3} × 7 - 13 \frac{1}{3} × 2 = wrong answer! This breaks up the parentheses incorrectly and gives 16 - 73 \frac{7}{3} - 23 \frac{2}{3} = 13. Always solve what's inside parentheses first, then multiply by the coefficient.

Practice Quiz

Test your knowledge with interactive questions

What will be the result of this algebraic expression:

\( 5x-6 \)

if we place

\( x=8 \)

FAQ

Everything you need to know about this question

Why do I substitute the values first?

+

Substituting values for variables transforms the algebraic expression into arithmetic. This makes it much easier to follow the order of operations and avoid mistakes with the variables.

What happens if I don't solve the parentheses first?

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You'll get the wrong answer! The expression 13(7+2) \frac{1}{3}(7+2) means multiply 13 \frac{1}{3} by the sum of 7 and 2, not multiply each term separately.

How do I multiply a fraction by a whole number?

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Multiply the numerator by the whole number: 13×9=93=3 \frac{1}{3} \times 9 = \frac{9}{3} = 3 . The denominator stays the same!

Can I convert the fraction to a decimal first?

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Yes! 130.333... \frac{1}{3} \approx 0.333... but this creates repeating decimals that are harder to work with. Keep fractions as fractions for exact answers.

What if I get confused with the negative sign?

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Remember that 8ab(7+a) 8a - b(7+a) means 8a+(b)(7+a) 8a + (-b)(7+a) . Since b is positive 13 \frac{1}{3} , we're subtracting a positive result.

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