Solve the Expression: 8(x-7)+4(6-2y) with x=7.1 and y=5/8

Question

What will be the result of this algebraic expression:

8(x7)+4(62y) 8(x-7)+4(6-2y)

if we place

x=7.1,y=58 x=7.1,y=\frac{5}{8}

Video Solution

Solution Steps

00:00 Substitute and solve
00:03 Let's substitute appropriate values according to the given data and solve
00:22 Always solve parentheses first
00:29 Always solve multiplication and division before addition and subtraction
00:33 Negative times positive always equals negative
00:44 Continue solving according to the correct order of operations
01:03 And this is the solution to the question

Step-by-Step Solution

To solve the problem, we need to substitute the given values into the expression and simplify:

  • Step 1: Substitute x=7.1 x = 7.1 into the expression 8(x7) 8(x-7) .
    This gives us 8(7.17)=8(0.1)=0.8 8(7.1-7) = 8(0.1) = 0.8 .
  • Step 2: Substitute y=58 y = \frac{5}{8} into the expression 4(62y) 4(6-2y) .
    First, calculate 2y=2×58=108=1.25 2y = 2 \times \frac{5}{8} = \frac{10}{8} = 1.25 .
    Then, 61.25=4.75 6 - 1.25 = 4.75 .
    Finally, 4(4.75)=19 4(4.75) = 19 .
  • Step 3: Add the results from Step 1 and Step 2.
    That is 0.8+19=19.8 0.8 + 19 = 19.8 .

Therefore, the result of the expression 8(x7)+4(62y) 8(x-7) + 4(6-2y) with x=7.1 x = 7.1 and y=58 y = \frac{5}{8} is 19.8\mathbf{19.8}.

Answer

19.8 19.8