Solve |a|-|18-9|+|4|<0: Multiple Absolute Value Inequality Analysis

Absolute Value Inequalities with Multiple Terms

Given:

a189+4<0 |a|-|18-9|+|4|<0

Which of the following statements is necessarily true?

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1

Understand the problem

Given:

a189+4<0 |a|-|18-9|+|4|<0

Which of the following statements is necessarily true?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Simplify the expression inside the inequality.
  • Determine the necessary condition for a a .
  • Compare the result with the provided options.

Step 1: Simplify the expression.
We start by evaluating the fixed absolute values:
189=9 |18 - 9| = 9 and 4=4 |4| = 4 .
Substituting these values into the inequality gives us:
a9+4<0.|a| - 9 + 4 < 0.

Step 2: Simplify further and solve for a |a| .
Combine constants:
a5<0 |a| - 5 < 0
Thus, we have:
a<5 |a| < 5 .

Step 3: Apply the property of absolute values.
The inequality a<5 |a| < 5 implies that:
5<a<5-5 < a < 5.

Therefore, the solution to the problem is 5<a<5 -5 < a < 5 .

3

Final Answer

5<a<5 -5 < a < 5

Key Points to Remember

Essential concepts to master this topic
  • Rule: Evaluate absolute values inside expressions before solving inequalities
  • Technique: Simplify |18-9| = 9 and |4| = 4 first
  • Check: Test boundary values: when a = 5, |5| - 5 = 0 (not < 0) ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to simplify constant absolute values first
    Don't try to solve |a| - |18-9| + |4| < 0 without evaluating the constants first = confusing expressions! This makes the problem unnecessarily complex. Always simplify |18-9| = 9 and |4| = 4 before working with the variable.

Practice Quiz

Test your knowledge with interactive questions

Given:

\( \left|2x-1\right|>-10 \)

Which of the following statements is necessarily true?

FAQ

Everything you need to know about this question

Why do I need to evaluate the constant absolute values first?

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Evaluating constants like 189=9 |18-9| = 9 and 4=4 |4| = 4 simplifies your work! This turns the complex expression into a5<0 |a| - 5 < 0 , which is much easier to solve.

How do I solve |a| < 5?

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When a<5 |a| < 5 , it means a is less than 5 units away from zero. This gives us 5<a<5 -5 < a < 5 , so a can be any number between -5 and 5.

What if I got |a| > 5 instead?

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If you have a>5 |a| > 5 , then a would be more than 5 units away from zero. This means a<5 a < -5 or a>5 a > 5 .

How can I check my answer?

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Test values from your solution! Try a=0 a = 0 : 09+4=5<0 |0| - 9 + 4 = -5 < 0 ✓. Try a=6 a = 6 : 69+4=1>0 |6| - 9 + 4 = 1 > 0

Why isn't a = 5 included in the solution?

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Because we need strict inequality (<). When a=5 a = 5 , we get 55=0 |5| - 5 = 0 , but we need the result to be less than 0, not equal to 0.

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