Solve Absolute Value Inequality: |3x - 1| < 5x Analysis

Question

Given:

3x1<5x \left|3x - 1\right| < 5x

Which of the following statements is necessarily true?

Step-by-Step Solution

Let's solve the inequality \left|3x - 1\right| < 5x :

  1. Remove the absolute value by considering two cases:

    1. 3x - 1 < 5x
      Solve for x x :

    2. 3x - 1 < 5x

      Subtract 3x 3x from both sides:
      -1 < 2x

      Divide both sides by 2 2 :
      -\frac{1}{2} < x

      Rewriting this inequality yields: x > -\frac{1}{2}

    3. -(3x - 1) < 5x
      Simplifying yields:

    4. -3x + 1 < 5x

      Add 3x 3x to both sides:
      1 < 8x

      Divide both sides by 8 8 :
      \frac{1}{8} < x

      This implies x > \frac{1}{8}

  2. Combine results:

  3. Both conditions imply x > \frac{1}{8} . Thus, the solution is x > \frac{1}{8} .

Answer

x > \frac{1}{8}