Solve |5x + 3| ≤ 7: Absolute Value Inequality Analysis

Question

Given:

5x+37 \left|5x + 3\right| \leq 7

Which of the following statements is necessarily true?

Step-by-Step Solution

To solve 5x+37 \left| 5x + 3 \right| \leq 7 , consider both cases:5x+37 5x + 3 \leq 7 and 5x+37 5x + 3 \geq -7 .

1. Solving 5x+37 5x + 3 \leq 7 :

5x+37 5x + 3 \leq 7

Subtract 3 from both sides:

5x4 5x \leq 4

Divide both sides by 5:

x0.8 x \leq 0.8

2. Solving 5x+37 5x + 3 \geq -7 :

5x+37 5x + 3 \geq -7

Subtract 3 from both sides:

5x10 5x \geq -10

Divide both sides by 5:

x2 x \geq -2

Combining both results, we find 2x0.8 -2 \leq x \leq 0.8 .

Answer

2x0.8 -2 \leq x \leq 0.8