Solve Addition Problem: Finding the Sum of 19 + 41

To solve the addition problem $19 + 41$, let's perform the following steps:

• Step 1: Align the numbers according to place value, so we have:

$\begin{array}{c c} & 19 \\ + & 41 \\ \hline \end{array}$

• Step 2: Add the units digits (9 and 1). $9 + 1 = 10$. This result implies a 0 in the units place and a carry-over of 1 to the tens column.
• Step 3: Add the tens digits plus any carry-over. We have $1 + 4 + 1 (carry) = 6$.

Thus, combining these we get: $\begin{array}{c c} & 19 \\ + & 41 \\ \hline & 60 \\ \end{array}$

Therefore, the sum of $19 + 41$ is $\textbf{60}$.