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To solve this problem, we'll break it down into manageable steps:
Let's add the units digits:
This results in a sum of 10. Place the 0 (which is the unit value) in the units place of the final answer, and carry over the 1 to the tens digit.
Let's add the tens digits, including the carry-over:
The result is 4, and there is no need to carry over this time.
Step 4: Combine the calculated digits. The tens digit is 4, and the units digit is 0 from our previous operation.
Thus, the final sum is .
Therefore, the solution to the problem is .
If we have 85 blocks in total, how many blocks will remain if we remove 4 tens and 1 one?
In our number system, each column can only hold one digit. When 1 + 9 = 10, the '1' belongs in the tens place and the '0' stays in the units place. Think of it like exchanging 10 ones for 1 ten!
You'll get the wrong answer! In this problem, forgetting the carried 1 gives you 30 instead of 40. Always remember to add any carried numbers to the next column.
Yes! You could think: 11 + 30 = 41, then subtract 1 to get 40. Or use the fact that 11 + 29 = 10 + 30 = 40. But learning the standard algorithm helps with bigger numbers!
Try these methods: 1) Add backwards: 29 + 11 should also equal 40. 2) Subtract: 40 - 11 should equal 29. 3) Use estimation: 10 + 30 = 40, so our answer makes sense!
Carrying means moving extra value to the next place value column. When digits add up to 10 or more, we can't fit it all in one column, so we 'carry over' the extra to where it belongs!
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