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To solve this problem, we'll break it down into manageable steps:
Let's add the units digits:
This results in a sum of 10. Place the 0 (which is the unit value) in the units place of the final answer, and carry over the 1 to the tens digit.
Let's add the tens digits, including the carry-over:
The result is 4, and there is no need to carry over this time.
Step 4: Combine the calculated digits. The tens digit is 4, and the units digit is 0 from our previous operation.
Thus, the final sum is .
Therefore, the solution to the problem is .
If we have 67 blocks in total, how many blocks will remain if we remove 5 tens and 4 ones?
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