Solve: Division of Mixed Numbers 5 4/5 ÷ 2 1/10

Question

545:2110= 5\frac{4}{5}:2\frac{1}{10}=

Video Solution

Solution Steps

00:04 Let's start by solving the problem.
00:07 First, we need to convert any mixed fractions into improper fractions.
00:31 Next, express the division as a fraction, like a numerator over a denominator.
00:42 Now, multiply by the reciprocal of the divisor. Just flip it upside down.
00:50 Great! Let's calculate the numerator by multiplying the top numbers.
00:57 Now, let's convert the result back to a mixed fraction.
01:01 Break down 290 into 210 plus 80, just to make it simpler.
01:08 Separate the fraction into a whole number part and a remainder.
01:14 Finally, reduce or simplify any parts that can be simplified.
01:23 Convert everything into a whole number, and combine it with the mixed number.
01:28 And there we have it, that's the solution to our question!

Step-by-Step Solution

To solve the problem 545÷2110 5\frac{4}{5} \div 2\frac{1}{10} , we follow these steps:

  • Step 1: Convert mixed numbers to improper fractions.
    545=5×5+45=25+45=295 5\frac{4}{5} = \frac{5 \times 5 + 4}{5} = \frac{25 + 4}{5} = \frac{29}{5}
  • 2110=2×10+110=20+110=2110 2\frac{1}{10} = \frac{2 \times 10 + 1}{10} = \frac{20 + 1}{10} = \frac{21}{10}
  • Step 2: Divide 295\frac{29}{5} by 2110\frac{21}{10} by multiplying by the reciprocal.
    295÷2110=295×1021\frac{29}{5} \div \frac{21}{10} = \frac{29}{5} \times \frac{10}{21}
  • Step 3: Multiply the fractions and simplify.
    295×1021=29×105×21=290105\frac{29}{5} \times \frac{10}{21} = \frac{29 \times 10}{5 \times 21} = \frac{290}{105}
  • Step 4: Simplify 290105\frac{290}{105}.
    Find the greatest common divisor (GCD) of 290 and 105. The GCD is 5.
    290÷5105÷5=5821\frac{290 \div 5}{105 \div 5} = \frac{58}{21}
  • Step 5: Convert the improper fraction 5821 \frac{58}{21} into a mixed number.
    58÷21=258 \div 21 = 2 remainder 1616, so 5821=21621 \frac{58}{21} = 2\frac{16}{21}

Therefore, the solution is 21621 2\frac{16}{21} .

Answer

21621 2\frac{16}{21}