Solve 7y(?-?)=-14xy+21: Finding Missing Terms in Linear Equations

Fill in the missing values:

7y(??)=14xy+21 7y(?-?)=-14xy+21

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:04 Factor 14 into factors 7 and 2
00:11 Multiply by the appropriate whole fraction
00:17 Factor 21 into factors 7 and 3
00:21 Mark the common factors
00:27 Take out the common factors from the parentheses
00:51 Substitute to get subtraction
01:00 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Fill in the missing values:

7y(??)=14xy+21 7y(?-?)=-14xy+21

2

Step-by-step solution

To solve this problem, we need to factor both sides of the equation 7y(??)=14xy+21 7y(?-?) = -14xy + 21 .

First, observe the terms on the right-hand side: 14xy -14xy and 21 21 .

  • Both terms share a common factor of 7. Factoring out 7 from both terms yields:

7(2xy+3) 7(-2xy + 3) .

Thus, the expression becomes:

7y(2x+3y) 7y(-2x + \frac{3}{y}) since the y was outside the parenthesis in the left.

Matching terms with 7y(??) 7y(? - ?) , the missing values are 3y \frac{3}{y} and 2x 2x .

Therefore, the solution is: 3y,2x \frac{3}{y}, 2x , corresponding to the correct choice.

3

Final Answer

3y,2x \frac{3}{y},2x

Practice Quiz

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Break down the expression into basic terms:

\( 4x^2 + 6x \)

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