Solve for Remaining Water: 1/12 Hourly Reduction Over 4 Hours

Fraction Subtraction with Repeated Operations

A full bottle of water has a small hole in it. Every hour the amount of water in the bottle decreases by112 \frac{1}{12} .

How much water remains in the bottle after 4 hours?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Found the remaining part in the bottle after 4 hours
00:03 Given the amount that decreased after 4 hours
00:05 Therefore, subtract the given amount from the whole
00:10 Convert the whole to the appropriate fraction
00:16 Subtract in the common denominator
00:20 Calculate the numerator
00:24 Reduce the fraction as much as possible
00:27 Make sure to divide both numerator and denominator
00:34 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

A full bottle of water has a small hole in it. Every hour the amount of water in the bottle decreases by112 \frac{1}{12} .

How much water remains in the bottle after 4 hours?

2

Step-by-step solution

To solve this problem, we'll subtract 112\frac{1}{12} from the full bottle (represented as '1' or 1212\frac{12}{12}) for each hour for a total of 4 hours:

  • Initially, the bottle is full: 1212\frac{12}{12}.
  • After 1 hour, subtract 112\frac{1}{12}:
    1212112=1112\frac{12}{12} - \frac{1}{12} = \frac{11}{12}.
  • After 2 hours, subtract another 112\frac{1}{12}:
    1112112=1012=56\frac{11}{12} - \frac{1}{12} = \frac{10}{12} = \frac{5}{6} after reduction.
  • After 3 hours, subtract another 112\frac{1}{12}:
    56112=1012112=912=34\frac{5}{6} - \frac{1}{12} = \frac{10}{12} - \frac{1}{12} = \frac{9}{12} = \frac{3}{4} after reduction.
  • After 4 hours, subtract another 112\frac{1}{12}:
    34112=912112=812=23\frac{3}{4} - \frac{1}{12} = \frac{9}{12} - \frac{1}{12} = \frac{8}{12} = \frac{2}{3} after reduction.

Therefore, the amount of water that remains in the bottle after 4 hours is 23\frac{2}{3}.

3

Final Answer

23 \frac{2}{3}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Subtract the same fraction repeatedly for each time period
  • Technique: Convert to common denominators: 34112=912112 \frac{3}{4} - \frac{1}{12} = \frac{9}{12} - \frac{1}{12}
  • Check: Total reduction should equal 4×112=412=13 4 \times \frac{1}{12} = \frac{4}{12} = \frac{1}{3}

Common Mistakes

Avoid these frequent errors
  • Adding fractions instead of subtracting
    Don't add 112 \frac{1}{12} each hour = water increases impossibly! The hole causes water to leak out, not fill up. Always subtract the fraction that represents the amount lost each hour.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \frac{3}{2}-\frac{1}{2}=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply 4 × 1/12 and subtract once?

+

You absolutely can! Both methods work perfectly. Subtracting 412=13 \frac{4}{12} = \frac{1}{3} from 1 gives 23 \frac{2}{3} . The step-by-step approach helps you understand what happens each hour.

How do I subtract fractions with different denominators?

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Find a common denominator first! For example, 34112 \frac{3}{4} - \frac{1}{12} becomes 912112=812 \frac{9}{12} - \frac{1}{12} = \frac{8}{12} , then simplify to 23 \frac{2}{3} .

What does 'full bottle' mean as a fraction?

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A full bottle represents the whole amount, which equals 1 or 1212 \frac{12}{12} when using twelfths. Think of it as 12 out of 12 parts!

Should I always reduce fractions to lowest terms?

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Yes, always simplify! 812 \frac{8}{12} reduces to 23 \frac{2}{3} by dividing both numerator and denominator by their greatest common factor (4).

What if the problem asked about 5 hours instead?

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Same process! After 5 hours: 15×112=1512=712 1 - 5 \times \frac{1}{12} = 1 - \frac{5}{12} = \frac{7}{12} would remain. The pattern continues for any number of hours.

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