A full bottle of water has a small hole in it. Every hour the amount of water in the bottle decreases by.
How much water remains in the bottle after 4 hours?
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A full bottle of water has a small hole in it. Every hour the amount of water in the bottle decreases by.
How much water remains in the bottle after 4 hours?
To solve this problem, we'll subtract from the full bottle (represented as '1' or ) for each hour for a total of 4 hours:
Therefore, the amount of water that remains in the bottle after 4 hours is .
Solve the following exercise:
\( \frac{3}{2}-\frac{1}{2}=\text{?} \)
You absolutely can! Both methods work perfectly. Subtracting from 1 gives . The step-by-step approach helps you understand what happens each hour.
Find a common denominator first! For example, becomes , then simplify to .
A full bottle represents the whole amount, which equals 1 or when using twelfths. Think of it as 12 out of 12 parts!
Yes, always simplify! reduces to by dividing both numerator and denominator by their greatest common factor (4).
Same process! After 5 hours: would remain. The pattern continues for any number of hours.
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