Solve for X:
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Solve for X:
The common denominator of 8, 3, and 5 is 120.
Now we multiply each numerator by the corresponding number to reach 120 and thus cancel the fractions and obtain the following equation:
We multiply the exercises in parentheses accordingly:
We will solve the left side (from left to right) and will obtain:
We reduce both sides by
We find that x is equal
\( x+7=14 \)
\( x=\text{?} \)
Find the least common multiple of all denominators. Since 8 = 2³, 3 = 3, and 5 = 5 have no common factors, multiply them: .
You multiply each fraction by whatever makes its denominator equal to 120. For , multiply by 15 because . This clears the fraction completely!
Negative answers are completely normal in algebra! The problem gives us , which is correct. Always check by substituting back into the original equation.
Check if 120 and 41 share any common factors. Since 41 is prime and doesn't divide 120, the fraction is already in simplest form.
Substitute back into . If the left side equals 1, your answer is correct!
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