Solve for X: (2/105)^x Expression with Product Denominator

Exponent Rules with Product Denominators

Insert the corresponding expression:

(23×5×7)x= \left(\frac{2}{3\times5\times7}\right)^x=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to a the power (N)
00:08 equals the numerator and denominator raised to the same power (N)
00:12 We will apply this formula to our exercise
00:20 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(23×5×7)x= \left(\frac{2}{3\times5\times7}\right)^x=

2

Step-by-step solution

To solve this problem, we need to express (23×5×7)x\left(\frac{2}{3 \times 5 \times 7}\right)^x by applying the rule for powers of a fraction.

Using the exponent rule (ab)x=axbx\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x}, we proceed as follows:

  • Step 1: Express the numerator and denominator with the exponent xx.
    The expression (23×5×7)x\left(\frac{2}{3 \times 5 \times 7}\right)^x becomes 2x(3×5×7)x\frac{2^x}{(3 \times 5 \times 7)^x}.
  • Step 2: Apply the power of a product rule to the denominator.
    This results in (3×5×7)x=3x×5x×7x(3 \times 5 \times 7)^x = 3^x \times 5^x \times 7^x.
  • Step 3: Substitute back into the fraction from Step 1.
    We get 2x3x×5x×7x\frac{2^x}{3^x \times 5^x \times 7^x}.

Therefore, the original expression (23×5×7)x\left(\frac{2}{3 \times 5 \times 7}\right)^x simplifies to 2x3x×5x×7x\frac{2^x}{3^x \times 5^x \times 7^x}.

The correct answer is: 2x3x×5x×7x \frac{2^x}{3^x \times 5^x \times 7^x} .

3

Final Answer

2x3x×5x×7x \frac{2^x}{3^x\times5^x\times7^x}

Key Points to Remember

Essential concepts to master this topic
  • Fraction Rule: (ab)x=axbx \left(\frac{a}{b}\right)^x = \frac{a^x}{b^x} for any fraction with exponent
  • Product Rule: (abc)x=axbxcx (abc)^x = a^x \cdot b^x \cdot c^x distributes exponent to each factor
  • Check: Verify each factor has the exponent x applied individually ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only part of the denominator
    Don't write 2x3×5×7x \frac{2^x}{3 \times 5 \times 7^x} by only applying x to the last factor! This ignores the product rule and gives an incomplete answer. Always apply the exponent to every single factor in the product: (3×5×7)x=3x×5x×7x (3 \times 5 \times 7)^x = 3^x \times 5^x \times 7^x .

Practice Quiz

Test your knowledge with interactive questions

\( (3\times4\times5)^4= \)

FAQ

Everything you need to know about this question

Why can't I just put the exponent on the whole denominator like 2(3×5×7)x \frac{2}{(3 \times 5 \times 7)^x} ?

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That's actually mathematically correct too! But the question asks you to expand the expression fully. Think of it like expanding (abc)2=a2b2c2 (abc)^2 = a^2b^2c^2 instead of leaving it as (abc)2 (abc)^2 .

Do I need to apply the exponent to the 2 in the numerator?

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Yes, absolutely! The fraction rule (ab)x=axbx \left(\frac{a}{b}\right)^x = \frac{a^x}{b^x} applies to both the numerator and denominator. So 2 becomes 2x 2^x .

What's the difference between 3x×5x×7x 3^x \times 5^x \times 7^x and (3×5×7)x (3 \times 5 \times 7)^x ?

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They're actually equal! The product rule says (abc)x=axbxcx (abc)^x = a^x \cdot b^x \cdot c^x . The first form is expanded while the second is factored. This question wants the expanded form.

How do I remember when to use the product rule?

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Look for multiplication inside parentheses with an exponent outside. Whenever you see (a×b×c)x (a \times b \times c)^x , the exponent x gets distributed to each factor: ax×bx×cx a^x \times b^x \times c^x .

Can I simplify 3×5×7 3 \times 5 \times 7 to 105 first?

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You could calculate 3×5×7=105 3 \times 5 \times 7 = 105 to get (2105)x \left(\frac{2}{105}\right)^x , but the question shows the denominator as separate factors. Keep them separate and apply the exponent to each: 3x×5x×7x 3^x \times 5^x \times 7^x .

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