Solve the Complex Fraction: (13/126)^(x+y) Expression Completion

Exponent Rules with Fractional Base

Insert the corresponding expression:

(137×6×3)x+y= \left(\frac{13}{7\times6\times3}\right)^{x+y}=

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1

Understand the problem

Insert the corresponding expression:

(137×6×3)x+y= \left(\frac{13}{7\times6\times3}\right)^{x+y}=

2

Step-by-step solution

Let's start by examining the expression given in the question:

(137×6×3)x+y \left(\frac{13}{7\times6\times3}\right)^{x+y}

This expression is a power of a fraction. There is a general rule in exponents which states:

(ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}

Using this rule, we will apply it to our original expression.

Given, a=13 a = 13 , b=7×6×3 b = 7\times6\times3 , and n=x+y n = x+y , we can rewrite our expression as:

13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}}

The solution to the question is:

13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}}

3

Final Answer

13x+y(7×6×3)x+y \frac{13^{x+y}}{\left(7\times6\times3\right)^{x+y}}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Apply the power to both numerator and denominator separately
  • Technique: (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} transforms complex fractions into manageable parts
  • Check: Verify denominator has parentheses around entire product: (7×6×3)x+y (7\times6\times3)^{x+y}

Common Mistakes

Avoid these frequent errors
  • Forgetting to apply exponent to entire denominator
    Don't write 13x+y7×6×3 \frac{13^{x+y}}{7\times6\times3} = wrong answer! This only applies the exponent to the numerator, leaving the denominator unchanged. Always apply the exponent to both parts: 13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}} .

Practice Quiz

Test your knowledge with interactive questions

\( (3\times4\times5)^4= \)

FAQ

Everything you need to know about this question

Why do I need parentheses around the entire denominator?

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The parentheses show that the entire product 7×6×3 7\times6\times3 gets raised to the power x+y x+y . Without them, only the last number (3) would get the exponent!

What's the difference between the correct and incorrect answers?

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The correct answer 13x+y(7×6×3)x+y \frac{13^{x+y}}{(7\times6\times3)^{x+y}} applies the exponent to both parts of the fraction. The wrong answers either forget the exponent on the denominator or apply it incorrectly.

Can I simplify 7×6×3 first before applying the exponent?

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Yes! You can calculate 7×6×3=126 7\times6\times3 = 126 first, giving you 13x+y126x+y \frac{13^{x+y}}{126^{x+y}} . Both forms are mathematically equivalent.

Does this rule work for any fraction raised to a power?

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Absolutely! The rule (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} works for any fraction and any exponent. It's one of the fundamental exponent laws.

What if the exponent was negative?

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The same rule applies! A negative exponent would flip the fraction first, then apply the positive power. But the basic principle of applying the exponent to both parts remains unchanged.

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