What is the value of x?
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What is the value of x?
Let's solve the equation, first we'll simplify the algebraic expressions using the perfect square binomial formula:
We will then apply the mentioned formula and expand the parentheses in the expression in the equation:
We'll continue and combine like terms, by moving terms between sides. Then we can notice that the squared term cancels out, therefore it's a first-degree equation, which we'll solve by isolating the variable term on one side and dividing both sides of the equation by its coefficient:
Therefore, the correct answer is answer B.
Choose the expression that has the same value as the following:
\( (x+y)^2 \)
When you expand both sides, you get x^2 + 6x + 9 = x^2 + 15. The x^2 terms are identical on both sides, so they cancel out when you subtract, leaving just 6x + 9 = 15.
The middle term is 2ab from the formula (a+b)^2 = a^2 + 2ab + b^2. Here, a = x and b = 3, so the middle term is 2 \cdot x \cdot 3 = 6x.
Not easily! You could try taking square roots of both sides, but that gets complicated with the mixed terms. Expanding using the binomial formula is the most straightforward approach.
Think "First, Outer, Inner, Last" or remember the pattern:
Let's check: (3+3)^2 = 36 but 3^2 + 15 = 24. Since 36 ≠ 24, x = 3 doesn't work. Always verify your answer!
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